A student says that a speed of 50 m/s is faster than a speed of 140 km/h because the number is bigger. What would you say to the
1 answer:
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Answer:
Explanation:
The electric field applies a force qE, but only in the y direction. This means that the x component of the
momentum must be conserved:
0 = Fx =dpx/dt
=⇒ px is conserved
pxi = γimvxi = pxf = γfmvxf (see the attactments)
the particle will acquire a velocity in the y
direction, and vxf <vxi. The x-component of the velocity, and thus the x-component of the momentum
must decrease.
Answer:
F = 10 N
Explanation:
- Assuming that we can treat to both particles as point charges, the magnitude of the force that one charge exerts on the other, must obey Coulomb's Law.
- The expression for this force, applied to the charges +Q and +q, separated by a distance d, is as follows:
- If we replace +Q by +4Q, and d by 2*d, the new expression for the magnitude of the force is as follows:
- As it can be seen, the force will be as same as before making changes, so F= 10 N.
Explanation:
The given data is as follows.
mass = 0.20 kg
displacement = 2.6 cm
Kinetic energy = 1.4 J
Spring potential energy = 2.2 J
Now, we will calculate the total energy present present as follows.
Total energy = Kinetic energy + spring potential energy
= 1.4 J + 2.2 J
= 3.6 Joules
As maximum kinetic energy of the object will be equal to the total energy.
So, K.E = Total energy
= 3.6 J
Also, we know that
K.E =
or, v =
=
=
= 6 m/s
thus, we can conclude that maximum speed of the mass during its oscillation is 6 m/s.