The interval that f(x) is increasing is the distance from 200 to 300.
The minimum value of f(x) in the interval 0<x<300 is 200.
At a value of 500, the value of f(x) is 0.
The function can't be a quadratic function since there are two points in the graph where f(x) changes its rate from increasing to decreasing or the opposite. A quadratic function has only one of that point.
Answer:
t = 74 / 9
Step-by-step explanation:
-9(t - 2) = 4(1 - 15)
-9t + 18 = 4 - 60
-9t + 18 = -56
-18 -18
-9t = -74
/-9 /-9
t = 74 / 9
t = 8.22
<h3>
Answer: Give the domain and the range of each quadratic function whose graph is described. The vertex is (−1,−2)(−1,−2) and the parabola opens up.</h3>
If this is a graph, I attached the file.
The minimum is (122.222, 3277.778)
The y intercept is (0,10000)
The graph: .45x^2-110x+10000
Answer:
Step-by-step explanation:
(x+4)² + y² = 1.5²
