Answer:
I can help with Q "4" as -
It uses triangle congruence test - here we use - SAS, as
one side is equal as it is given
both the angles are 90 degree
and they share a same side
so -
8x = 6x + 5
8x - 6x = 5
2x = 5
x = 2.5
RU = 6x+ 5 = 6 (2.5) + 5 = 20
( I am not so sure but I think this is the answer )
STEP-BY-STEP EXPLANATION:
Given information
The given ordered point = (5, 0)
Step 1: We need to translate the point 4 units down
To translate down means we will be subtracting a value from the y--axis
Hence, we have
When translated 4 units down, we got (5, -4)
Step 2: Reflect over the y-axis
The general rule for reflecting over the y-axis is (-x, y)
This means the value of x will be negated and the value of y will remain the same
Step 3: the graph the point
Solutions
To solve this problem we have to use the Pythagorean theorem. You can only use the Pythagorean theorem in Right Triangles. The longest side of the triangle is called the "hypotenuse". C² is the longest side so it is the hypotenuse . To calculate c² we have to do α² + β² = c².
Given
One leg of a right triangular piece of land has a length of 24 yards. They hypotenuse has a length of 74 yards. The other leg has a length of 10x yards.
First leg (24 yards) would be α
Second leg would be β
Hypotenuse (74 yards) would be c
Now we have points α β c.
a² (24) + β² ( x ) = c² (74)
Calculations
c² = α² + β²
74² = 24²+ β²
<span>5476 = 576 + </span>β²
5476 - 576 = β²
<span> </span>
<span>4900 = </span>β²
→√4900
<span> </span>
β<span> = 70 yards
</span>
<span>70 = 10x
</span>
<span>x = 70</span>÷<span>10 = 7 yards
</span>
The second leg = 7 yards
Answer:
f(2n)-f(n)=log2
b.lg(lg2+lgn)-lglgn
c. f(2n)/f(n)=2
d.2nlg2+nlgn
e.f(2n)/(n)=4
f.f(2n)/f(n)=8
g. f(2n)/f(n)=2
Step-by-step explanation:
What is the effect in the time required to solve a prob- lem when you double the size of the input from n to 2n, assuming that the number of milliseconds the algorithm uses to solve the problem with input size n is each of these function? [Express your answer in the simplest form pos- sible, either as a ratio or a difference. Your answer may be a function of n or a constant.]
from a
f(n)=logn
f(2n)=lg(2n)
f(2n)-f(n)=log2n-logn
lo(2*n)=lg2+lgn-lgn
f(2n)-f(n)=lg2+lgn-lgn
f(2n)-f(n)=log2
2.f(n)=lglgn
F(2n)=lglg2n
f(2n)-f(n)=lglg2n-lglgn
lg2n=lg2+lgn
lg(lg2+lgn)-lglgn
3.f(n)=100n
f(2n)=100(2n)
f(2n)/f(n)=200n/100n
f(2n)/f(n)=2
the time will double
4.f(n)=nlgn
f(2n)=2nlg2n
f(2n)-f(n)=2nlg2n-nlgn
f(2n)-f(n)=2n(lg2+lgn)-nlgn
2nLg2+2nlgn-nlgn
2nlg2+nlgn
5.we shall look for the ratio
f(n)=n^2
f(2n)=2n^2
f(2n)/(n)=2n^2/n^2
f(2n)/(n)=4n^2/n^2
f(2n)/(n)=4
the time will be times 4 the initial tiote tat ratio are used because it will be easier to calculate and compare
6.n^3
f(n)=n^3
f(2n)=(2n)^3
f(2n)/f(n)=(2n)^3/n^3
f(2n)/f(n)=8
the ratio will be times 8 the initial
7.2n
f(n)=2n
f(2n)=2(2n)
f(2n)/f(n)=2(2n)/2n
f(2n)/f(n)=2
Answer:
60
Step-by-step explanation:
200*0.30=60
Multiply the percent's by the total cost.
