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Anastasy [175]
3 years ago
15

A dog is chasing a cat towards a tree. The cat has a 10-yard lead and runs at 6 yards per second. The dog runs at a speed of 8 y

ards per second. The tree is 30 yards away from the dog's starting position. Which animal will reach the tree first?

Physics
1 answer:
oksano4ka [1.4K]3 years ago
3 0

Answer : Cat will reach tree first.

Explanation :

It is given that,

Total distance between dog and tree is 30 yards. The cat has 10 yards lead. So, the distance between cat and tree is 20 yards.

Speed of cat  is 6 Yards/ sec.

Speed of dog is 8 Yards/sec.

speed of cat is, S_c=\dfrac{distance\ covered\ by\ cat}{time\ taken}

6\ Yards/sec=\dfrac{20\ Yards}{t_c}

t_c=3.33\ sec

Now, speed of dog is, S_d=\dfrac{distance\ covered\ by\ dog}{time\ taken}

8\ Yards/sec=\dfrac{30\ yards}{t_d \ sec}

t_d=3.75\ sec

It is clear that, cat is taking less time as compared with dog. So, the cat will reach tree first.

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a) the magnitude of the force is

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b)  the magnitude of the torque on the dipole

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Explanation:

from coulomb's law

E = \frac{kq}{r^{2} }

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the expression of the electric field due to dipole at a distance r is

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b) b) magnitude of the torque(τ) on the dipole is dependent on the perpendicular forces

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θ = 90°

note: sin90° = 1

τ = F × r

recall  F = Qqs/4πε₀r³

∴ τ = (Qqs/4πε₀r³) × r

τ = Qqs/4πε₀r²

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