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Anastasy [175]
3 years ago
15

A dog is chasing a cat towards a tree. The cat has a 10-yard lead and runs at 6 yards per second. The dog runs at a speed of 8 y

ards per second. The tree is 30 yards away from the dog's starting position. Which animal will reach the tree first?

Physics
1 answer:
oksano4ka [1.4K]3 years ago
3 0

Answer : Cat will reach tree first.

Explanation :

It is given that,

Total distance between dog and tree is 30 yards. The cat has 10 yards lead. So, the distance between cat and tree is 20 yards.

Speed of cat  is 6 Yards/ sec.

Speed of dog is 8 Yards/sec.

speed of cat is, S_c=\dfrac{distance\ covered\ by\ cat}{time\ taken}

6\ Yards/sec=\dfrac{20\ Yards}{t_c}

t_c=3.33\ sec

Now, speed of dog is, S_d=\dfrac{distance\ covered\ by\ dog}{time\ taken}

8\ Yards/sec=\dfrac{30\ yards}{t_d \ sec}

t_d=3.75\ sec

It is clear that, cat is taking less time as compared with dog. So, the cat will reach tree first.

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Explanation:

The net force along North-South direction is 18-24=-6 N.

The net force along East-West direction is 16-16=0 N

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By Newton's Second law,

Force F=ma

Therefore acceleration a=F/m

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A certain unbalanced force gives a 5kg object an acceleration of 15 m/s2. What would be the acceleration if the same force was a
stira [4]

Answer:

a2 = 2.5 m/s2

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If you walk 1.2 km north and then 1.6 km east, what are the magnitude and direction of your resultant displacement?
vodomira [7]

<u>Answer:</u>

 Option A is the correct answer.

<u>Explanation:</u>

  Let the east point towards positive X-axis and north point towards positive Y-axis.

 First walking 1.2 km north,  displacement = 1.2 j km

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Answer:

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