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Harlamova29_29 [7]
3 years ago
9

A 2-inch, f/6 telescope has a 3-inch eyepiece focal. Its magnifying power is:

Physics
1 answer:
snow_tiger [21]3 years ago
5 0
The choices can be found elsewhere and as follows:

a. 5X 
b. 6X 
c. 15X 
<span>d. 60X 
</span>
I believe the correct answer from the choices listed is option C. <span>A 2-inch, f/6 telescope has a 3-inch eyepiece focal. Its magnifying power is 15x. Hope this answers the question. Have a nice day.</span>
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If the moment acting on the cross section is M=630N⋅m, determine the maximum bending stress in the beam. Express your answer to
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Answer:

2.17 Mpa

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The location of neutral axis from the top will be

\bar y=\frac {(240\times 25)\times \frac {25}{2}+2\times (20\times 150)\times (25+(\frac {150}{2}))}{(240\times 25)+2\times (20\times 150)}=56.25 mm

Moment of inertia from neutral axis will be given by \frac {bd^{3}}{12}+ ay^{2}

Therefore, moment of inertia will be

\frac {240\times 25^{3}}{12}+(240\times 25)\times (56.25-25/2)^{2}+2\times [\frac {20\times 150^{3}}{12}+(20\times 150)\times ((25+150/2)-56.25)^{2}]=34.5313\times 10^{6} mm^{4}}

Bending stress at top= \frac {630\times 10^{3}\times (175-56.25)}{34.5313\times 10^{6}}=2.1665127\approx 2.17 Mpa

Bending stress at bottom=\frac {630\times 10^{3}\times 56.25}{34.5313\times 10^{6}}=1.026242858\approx 1.03 Mpa

Comparing the two stresses, the maximum stress occurs at the bottom and is 2.17 Mpa

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