Answer:
a) 
.
b) 
.
Explanation:
a) What is the speed of the rock just before it hits the street?
From Kinematics we have 
.
If we take the top of the roof as the position 
, then
and we have (also, 
) :
⇒ 
⇒ .
b) How much time elapses from when the rock is thrown until it hits the street?
From Kinematics we have 
When the rock touches the ground:
With a minus sign to indicate the vector velocity points down.
(remember that 
)
Answer:
2.05 kgm²/s
Explanation:
I = moment of inertia of cylinder = 0.016 kgm²
r = radius of the cylinder = 6 cm = 0.06 m
v = linear speed of the cylinder = 7.7 m/s
w = angular speed of cylinder
Using the equation
v = r w
7.7 = (0.06) w
w = 128.33 rad/s
Magnitude of angular momentum of the cylinder is given as
L = I w
L = (0.016) (128.33)
L = 2.05 kgm²/s
Answer: The options are not given,
Here are the options.
A. channel
B. feedback
C. message
D. sender
The correct option is C
MESSAGE.
Explanation:
It is message because it is written or verbal or recorded words or communication or ideas transmitted by the sender to the receiver.
It include three aspects, content, structure and style.
The content entails the information and communication, how the information is important, useful and can be read to comprehend.
The structure of a message entails the tone .
The style include how the sender compose and write the message.
Answer:
At a deceleration of 60g, or 60 times the acceleration due to gravity a person will travel a distance of 0.38 m before coing to a complete stop
Explanation:
The maximum acceleration of the airbag = 60 g, and the duration of the acceleration = 36 ms or 36/1000 s or 0.036 s
To find out how far (in meters) does a person travel in coming to a complete stop in 36 ms at a constant acceleration of 60g
we write out the equation of motion thus.
S = ut + 0.5at²
wgere
S = distance to come to complete stop
u = final velocoty = 0 m/s
a = acceleration = 60g = 60 × 9.81
t = time = 36 ms
as can be seen, the above equation calls up the given variable as a function of the required variable thus
S = 0×0.036 + 0.5×60×9.81×0.036² = 0.38 m
At 60g, a person will travel a distance of 0.38 m before coing to a complete stop
