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Thepotemich [5.8K]
3 years ago
15

A 480 kg car moving at 14.4 m/s hits from behind another car moving at 13.3 m/s in the same direction. If the second car has a m

ass of 570 kg and a new speed of 17.9 m/s, what is the velocity of the first car after the collision?
Physics
1 answer:
Nostrana [21]3 years ago
5 0

Answer:

Velocity of the first car after the collision, v_1=8.93\ m/s

Explanation:

It is given that,

Mass of the car, m_1 = 480\ kg

Initial speed of the car, u_1 = 14.4\ m/s    

Mass of another car, m_2 = 570\ kg

Initial speed of the second car, u_2 = 13.3\ m/s  

New speed of the second car, v_2 = 17.9\ m/s  

Let v_1 is the final speed of the first car after the collision. The total momentum of the system remains conserved, Using the conservation of momentum to find it as :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

m_1u_1+m_2u_2-m_2v_2=m_1v_1

480\times 14.4+570\times 13.3-570\times 17.9=480v_1

v_1=8.93\ m/s

So, the velocity of the first car after the collision is 8.93 m/s. Hence, this is the required solution.

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