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Thepotemich [5.8K]
3 years ago
15

A 480 kg car moving at 14.4 m/s hits from behind another car moving at 13.3 m/s in the same direction. If the second car has a m

ass of 570 kg and a new speed of 17.9 m/s, what is the velocity of the first car after the collision?
Physics
1 answer:
Nostrana [21]3 years ago
5 0

Answer:

Velocity of the first car after the collision, v_1=8.93\ m/s

Explanation:

It is given that,

Mass of the car, m_1 = 480\ kg

Initial speed of the car, u_1 = 14.4\ m/s    

Mass of another car, m_2 = 570\ kg

Initial speed of the second car, u_2 = 13.3\ m/s  

New speed of the second car, v_2 = 17.9\ m/s  

Let v_1 is the final speed of the first car after the collision. The total momentum of the system remains conserved, Using the conservation of momentum to find it as :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

m_1u_1+m_2u_2-m_2v_2=m_1v_1

480\times 14.4+570\times 13.3-570\times 17.9=480v_1

v_1=8.93\ m/s

So, the velocity of the first car after the collision is 8.93 m/s. Hence, this is the required solution.

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A transformer with X turns in primary coil and Y turns in secondary coil is used to change the magnitude of voltage to 240 V. Ca
Vinil7 [7]

The input voltage is 120 V and the transformer is a step up transformer due to increase in the voltage induced in the secondary coil.

<h3>Input voltage </h3>

The input voltage of the transformer is the voltage of the primary coil and it is calculated as follows;

Ns/Np = Es/Ep

where;

  • Ns is the number of turn in the secondary coil
  • Np is the number of turn in the primary coil
  • Es is the secondary voltage
  • Ep is the primary voltage

2X/X = 240/Ep

2 = 240/Ep

Ep = 240/2

Ep = 120 V

Thus, the transformer is a step up transformer due to increase in the voltage induced in the secondary coil.

Learn more about transformer here: brainly.com/question/25886292

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FIGURE 1 shows part of a mass spectrometer. The whole arrangement is in a vacuum. Negative ions of mass 2.84 x 10-20 kg and char
yuradex [85]

Yes, the ions can exit slit P without being deflected, if the electric field strength is 170.6 N/C

Explanation:

When the ions are inside the container, they are subjected to two forces, with directions opposite to each other:

  • The force due to the electric field, whose magnitude is F_E=qE, where q is the charge of the ion and E is the strength of the electric field
  • The force due to the magnetic field, whose magnitude is F_B=qvB, where v is the speed of the ions and B is the strength of the magnetic field

The ions will move straight and undeflected if the two forces are equal and opposite. By using Fleming Left Hand rule, we notice that the magnetic force on the (negative) ions point upward: this means that the electric field must be also upward (so that the electric force on the ions is downward). Then, the two forces are balanced if

F_E = F_B

which translates into

qE=qvB\\\rightarrow v = \frac{E}{B}

Therefore, if the speed of the ions is equal to this ratio, the ions will go undeflected.

We can even calculate the value of E at which this occurs. In fact, we know that the ions are earlier accelerated by a potential difference V=-3000 V, so we have that their kinetic energy is given by the change in electric potential energy:

qV=\frac{1}{2}mv^2

where

q=-2.0\cdot 10^{-19}C\\m=2.84\cdot 10^{-20}kg

Solving for v, the speed,

v=\sqrt{\frac{2qV}{m}}=\sqrt{\frac{2(-2.0\cdot 10^{-19})(-3000)}{2.84\cdot 10^{-20}}}=205.6 m/s

And since the magnetic field strength is

B = 0.83 T

The strength of the electric field must be

E=vB=(205.6 m/s)(0.83 T)=170.6 N/C

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