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Thepotemich [5.8K]

3 years ago

15

A 480 kg car moving at 14.4 m/s hits from behind another car moving at 13.3 m/s in the same direction. If the second car has a m

ass of 570 kg and a new speed of 17.9 m/s, what is the velocity of the first car after the collision?

1 answer:

Nostrana [21]3 years ago

5 0

Answer:

Velocity of the first car after the collision, $v_1=8.93\ m/s$

Explanation:

It is given that,

Mass of the car, $m_1 = 480\ kg$

Initial speed of the car, $u_1 = 14.4\ m/s$

Mass of another car, $m_2 = 570\ kg$

Initial speed of the second car, $u_2 = 13.3\ m/s$

New speed of the second car, $v_2 = 17.9\ m/s$

Let $v_1$ is the final speed of the first car after the collision. The total momentum of the system remains conserved, Using the conservation of momentum to find it as :

$m_1u_1+m_2u_2=m_1v_1+m_2v_2$

$m_1u_1+m_2u_2-m_2v_2=m_1v_1$

$480\times 14.4+570\times 13.3-570\times 17.9=480v_1$

$v_1=8.93\ m/s$

So, the velocity of the first car after the collision is 8.93 m/s. Hence, this is the required solution.

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masya89 [10]

Answer:

Explanation:

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3 years ago

Hooke's law describes a certain light spring of unstretched length 34.8 cm. When one end is attached to the top of a doorframe a

DaniilM [7]

Answer:

a) $k = 1343.6\,\frac{N}{m}$ , b) $l = 0.501\,m\,(50.1\,cm)$

Explanation:

a) The Hooke's law states that spring force is directly proportional to change in length. That is to say:

$F \propto \Delta l$

In this case, the force is equal to the weight of the object:

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$F = (8.22\,kg)\cdot (9.807\,\frac{m}{s^{2}} )$

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The spring constant is:

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$k = \frac{80.614\,N}{0.408\,m-0.348\,m}$

$k = 1343.6\,\frac{N}{m}$

b) The length of the spring is:

$F = k\cdot (l-l_{o})$

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3 years ago

Whats the force of gravitation of a 10kg rock and 100kg boulder which are 5 meters apart

spayn [35]

Answer:

F = 2.6692 x 10⁻⁹ N

Explanation:

Given,

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The mass of the boulder, M = 100 kg

The distance between them, d = 5 m

The gravitational force between the two bodies is proportional to the product of their masses and inversely proportional to the square of the distance between them. It is given by the formula

<em> F = GMm/d² newton</em>

Where,

G - Universal gravitational constant

Substituting the given values,

F = 6.673 x 10⁻¹¹ x 100 x 10 / 5²

F = 2.6692 X 10⁻⁹ N

Hence, the force between the two bodies is, F = 2.6692 X 10⁻⁹ N

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3 years ago

A circuit contains a 1.5 volt battery and a bulb with a resistance of 3 ohms. Calculate the current

Vitek1552 [10]

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4 years ago

When the current in a toroidal solenoid is changing at a rate of 0.0240 A/s , the magnitude of the induced emf is 12.4 mV . When

Gemiola [76]

Answer:

The number of turns in the solenoid is 230.

Explanation:

Given that,

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Current, I = 1.5 A

Magnetic flux, $\phi=0.00338\ Wb$

The induced emf through the solenoid is given by :

$\epsilon=L\dfrac{dI}{dt}$

or

$L=\dfrac{\epsilon}{(di/dt)}$ ........(1)

The self inductance of the solenoid is given by :

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From equation (1) and (2) we get :

$\dfrac{\epsilon}{(di/dt)}=\dfrac{N\phi}{I}$

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N = 229.28 turns

or

N = 230 turns

So, the number of turns in the solenoid is 230. Hence, this is the required solution.

3 0

3 years ago