Answer:
1. Sine A = 3/5
2. Cos A = 4/5
3. Tan A = 3/4
4. Sine B = 4/5
5. Cos B = 3/5
6. Tan B = 4/3
Step-by-step explanation:
1. Determination of Sine A
Opposite = 3 in
Hypothenus = 5 in
Sine A =?
Sine A = opposite / Hypothenus
Sine A = 3/5
2. Determination of Cos A
Adjacent = 4 in
Hypothenus = 5 in
Cos A =?
Cos A = Adjacent / Hypothenus
Cos A = 4/5
3. Determination of Tan A
Opposite = 3 in
Adjacent = 4 in
Tan A =?
Tan A = opposite / Adjacent
Tan A = 3/4
4. Determination of Sine B
Opposite = 4 in
Hypothenus = 5 in
Sine B =?
Sine B = Opposite / Hypothenus
Sine B = 4/5
5. Determination of Cos B
Adjacent = 3 in
Hypothenus = 5 in
Cos B =?
Cos B = Adjacent / Hypothenus
Cos B = 3/5
6. Determination of Tan B
Opposite = 4 in
Adjacent = 3 in
Tan B =?
Tan B = opposite / Adjacent
Tan B = 4/3
Answer:16
Step-by-step explanation:
Start with whats inside (11+6) (17) then you will multiply 7 and 4 = 28+5 =33 then back to 17,,,, 33-17=16
Hello :
(-6a)-(-3a) =(-3a)-(0) = (0)-(3a) = (3a)-(6a) = -3a (arthmetic<span> sequence, the common - diff is : d= -3a the first term is : U1 = 6a
</span><span>a general rule for the n th term is : Un =U1+(n-1)d
Un = 6a +(n-1)(-3a) =
Un = 6a -3an+3a
</span>Un = -3an +9a
Answer:
1) Equation's:
2) Number of guest and the charge:
- Cost is same for both at 50 meals. The cost is $1250.
<u>Part 1</u>
Turn sentences into equation's (Let 'y' be total cost and x per meal) :
(i) charges $500 and $15 per meal
(ii) charges $350 and $18 per meal
<u>Part 2</u>
y = y
500 + 15x = 350 + 18x
18x - 15x = 500 - 350
3x = 150
x = 150/3
x = 50
Charge at guest's 50 meal:
y = 500 + 15(50)
y = $1250
Point : (50, 1250)
