Which of the following is a which of the following is a rational number?

Mathematics

1 answer:

Nastasia [14]3 years ago

5 0

Answer:

A. √25

General Formulas and Concepts:

Math

Rational Numbers - numbers that can be written as integers, terminating decimals, or fractions
Irrational Numbers - numbers that have non-terminating decimals i.e infinite decimals and cannot be written into a fraction

Step-by-step explanation:

Step 1: Define

A. √25

B. √123

C. √20

D. π

Step 2: Identify

A. √25 = 5; Rational

B. √123 ≈ 11.0905...; Irrational

C. √20 = 2√5 ≈ 4.47214...; Irrational

D. π ≈ 3.1415926535897932384626433832795...; Irrational

Therefore, our answer choice is A.

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Answer:

y = $C_1e^{3t}+C_2e^{6t}$ + $\dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})$

Step-by-step explanation:

y''- 9 y' + 18 y = t²

solution of ordinary differential equation

using characteristics equation

m² - 9 m + 18 = 0

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now calculating P.I.

$P.I. = \frac{t^2}{D^2 - 9D +18}$

$P.I. = \dfrac{t^2}{(D-3)(D-6)}\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(1-\frac{D}{6})^{-1}(t^2)\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(1+\frac{D}{6}+\frac{D^2}{36}+....)(t^2)\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(t^2+\frac{2t}{6} + \frac{2}{36})\\P.I. =\dfrac{1}{18}(1+\frac{D}{3}+\frac{D^2}{9}+....)(t^2+\frac{2t}{6} + \frac{2}{36})\\P.I. =\dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})$