Question

The graph of the equation LaTeX: x^2+y^2-20x+14y+28=0

Answer 1

Answer:

radius = 11

Step-by-step explanation:

The equation of a circle in general form is

x² + y² + 2gx + 2fy + c = 0

with radius = $\sqrt{g^2+f^2-c}$

x² + y² - 20x + 14y + 28 = 0 ← is in general form

with 2g = - 20 ⇒ g = - 10

2f = 14 ⇒ f = 7 and c = 28, thus

radius = $\sqrt{(-10)^2+7^2-28}$ = $\sqrt{100+49-28}$ = $\sqrt{121}$ = 11