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Mazyrski [523]
3 years ago
10

Please Explain it to me I really need help with this if you can I will mark u brainliest​

Physics
1 answer:
alexandr1967 [171]3 years ago
3 0

Answer:

I think it's letter b but I couldn't be sure

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Astronomers observe a spectral analysis of a distant star where a particular element has a spectral line with a wavelength of 66
tekilochka [14]

Answer:

(a). The velocity of star is 8.1\times10^{6}\ m/s and the direction of star toward the earth.

(b). The shift is 0.0168 nm.

Explanation:

Given that,

Wavelength of spectral line = 663 nm

Wavelength of spectral line in lab = 645 nm

(a). We need to calculate the velocity

Using doppler's effect

\Delta \lambda=\dfrac{v}{c}\lambda

Where, \Delta\lambda= change in wavelength

v = velocity

c = speed of light

Put the value into the formula

663-645=\dfrac{v}{3\times10^{8}}\times663

v=\dfrac{3\times10^{8}(663-645)}{663}

v=8144796.38\ m/s

v=8.1\times10^{6}\ m/s

The direction of star toward the earth.

(b). Speed = 7800 m/s

We need to calculate the shift

Using formula of shift

\Delta \lambda=\lambda(\sqrt{\dfrac{1+\dfrac{v}{c}}{1-\dfrac{v}{c}}}-1)

Put the value into the formula

\Delta \lambda=645\times(\sqrt{\dfrac{1+\dfrac{7800}{3\times10^{8}}}{1-\dfrac{7800}{3\times10^{8}}}}-1)

\Delta\lambda=0.0168\ nm

This shift is small compare to the the movement of Earth around the sun.

Hence, (a). The velocity of star is 8.1\times10^{6}\ m/s and the direction of star toward the earth.

(b). The shift is 0.0168 nm.

7 0
3 years ago
a man is pulling a block with a mass of 6.2kg across a horizontal surface and accelerates the block at a rate of 0.50m/s.the coe
klasskru [66]
Mg = 6.2 x 9.81 = 60.822 This is also normal force. Coefficient of friction times normal force is the force due to friction: 60.822 x 0.24 = 14.6N F = MA so F(your force) - F(friction) = 6.2 x 0.5 = 3.1 Your answer is 3.1+ 14.6 I hope this is correct though I might be wrong.
7 0
3 years ago
Read 2 more answers
Match these items.
viva [34]
-- 'Ca' (Calcium) is an element.
-- The proton has a positive charge.
-- Nuclear fusion results in the synthesis of atoms of new elements.
-- H₂O (water) is a chemical compound. 
-- Nuclear fission is a decay of the nucleus.
-- The atomic number of an element is the number of protons 
      in each atom of it.
-- I suppose you're using the Greek letter  <span>η  ('eta', not 'nu') 
      to represent the neutron.
-- I suppose you're using ' e ' to represent the electron.
</span>
6 0
3 years ago
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What question was asked by Faraday that the narrator calls a leap
masha68 [24]
<span> If electricity and magnetism can create motion, can the reverse be true? Can motion and magnetism create electricity?</span>
4 0
3 years ago
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A Explain why the sound produced by the horn of an approaching car
aleksklad [387]
When a car approaches you, the sound waves that reach you have a shorter wavelength and a higher frequency. You hear a sound with a higher pitch. When the car moves away from you, the sound waves that reach you have a longer wavelength and lower frequency.

?? ⬇️

An approaching source moves closer during period of the sound wave so the effective wavelength is shortened, giving a higher pitch since the velocity of the wave is unchanged. Similarly the pitch of a receding sound source will be lowered.

The Doppler effect is an effect observed in light and sound waves as they move toward or away from an observer. One simple example of the Doppler effect is the sound of an automobile horn. Picture a person standing on a street corner. A car approaches, blowing its horn.

Comparing two waves of the same wavelength, a higher frequency is associated with faster movement. Comparing two waves of different wavelengths, a higher frequency doesn't always indicate faster movement, although it can. Waves of different wavelengths can have the same frequency.

The pitch of a sound is our ear's response to the frequency of sound. Whereas loudness depends on the energy of the wave. ... The pitch of a sound depends on the frequency while loudness of a sound depends on the amplitude of sound waves.
5 0
3 years ago
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