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2 years ago

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Jack and jill are married. this year jack earned $72,000 and jill earned $80,000 and they received $4,000 of interest income fro

m a joint savings account. how much gross income would jack report if he files married-filing-separate from jill?

1 answer:

MaRussiya [10]2 years ago

4 0

<span>If Jack is filing married-filing-separate he would report $76,000 gross income as head of household.</span>

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A 20 ohm lamp and a 5 ohm lamp are connected in series and placed across a potential difference of 50 V.

iogann1982 [59]

Hi there!

1.

Since the two resistors are in series, we can simply add:
$R_T = R_1 + R_2 + ... R_n$

$R_T = 20 + 5 = \boxed{25 \Omega}$

2.

In series, the potential difference of each resistor (lamp) ADDS UP. We can begin by finding the current through the circuit using Ohm's law:
$V = IR\\\\I = \frac{V}{R_T}$

Plug in the values:
$I = \frac{50}{25} = 2 A$

Now,

we can use Ohm's law to find the individual voltage for each lamp.

20 Ohm lamp:
$V = 2 * 20 = \boxed{40 V}$

5 Ohm lamp:
$V = 2 * 5 = \boxed{10 V}$

3.

To solve, we can use the power equation.

$P (\text{Watts})= IV$

Plug in the values for each.

20 Ohm lamp:
$P = 2 * 40 = \boxed{80 W}$

5 Ohm lamp:
$P = 2 * 10 = \boxed{100 W}$

7 0

1 year ago

Speed training increases one's maximum velocity.<br> a. True<br> b. False

Harrizon [31]

That is absolutely true.

3 0

3 years ago

Read 2 more answers

State two factors that affect the spring constant of a spring made using a wire of a certain material and given thickness

MaRussiya [10]

The spring's rigidity is quantified by the spring constant. The spring constant increases as the wire's thickness increases. The spring constant lowers as the coil's diameter increases.

Material: Steel and copper are two materials that have differing constants when used to make identical springs.

Describe the spring constant ?

The restoring force applied to the spring for a given length of deflection is known as the spring constant. It is often referred to as the amount of force needed to extend or compress a spring one unit of length.

The level of resistance to spring deformation is expressed by the spring constant. In addition to being known as spring stiffness or spring rate, the spring constant and It is represented by the letter "K."

The following variables affect the coil spring's spring constant:-

a) Modulus of rigidity (G): As the modulus of rigidity of the spring material increases, so does the coil spring's spring constant.

b) Wire diameter (d): As the diameter of the spring wire grows, so does the spring constant.

c) Coil diameter (D): As the diameter of the spring coil increases, so does the spring's spring constant.

d) Number of coils (n): As the number of spring coils increases, the spring constant decreases.

To know more about spring constant :

brainly.com/question/14159361

#SPJ4

8 0

1 year ago

A spherical, non-conducting shell of inner radius = 10 cm and outer radius = 15 cm carries a total charge Q = 13 μC distributed

Vaselesa [24]

Answer:

E = 1580594.95 N/C

Explanation:

To find the electric field inside the the non-conducting shell for r=11.2cm you use the Gauss' law:

$\int EdS=\frac{Q_{in}}{\epsilon_o}$ (1)

dS: differential of the Gaussian surface

Qin: charge inside the Gaussian surface

εo: dielectric permittivity of vacuum = 8.85 × 10-12 C2/N ∙ m2

The electric field is parallel to the dS vector. In this case you have the surface of a sphere, thus you have:

$\int EdS=ES=E(4\pi r^2)$ (2)

Qin is calculate by using the charge density:

$Q_{in}=V_{in}\rho=\frac{4}{3}(r^3-a^3)\rho$ (3)

Vin is the volume of the spherical shell enclosed by the surface. a is the inner radius.

The charge density is given by:

$\rho=\frac{Q}{V}=\frac{13*10^{-6}C}{\frac{4}{3}\pi((0.15m)^3-(0.10m)^3)}\\\\\rho=1.30*10^{-3}\frac{C}{m^3}$

Next, you use the results of (3), (2) and (1):

$E(4\pi r^2)=\frac{4}{3\epsilon_o}(r^3-a^3)\rho\\\\E=\frac{\rho}{3\epsilo_o}(r-\frac{a^3}{r^2})$

Finally, you replace the values of all parameters, and for r = 11.2cm = 0.112m you obtain:

$E=\frac{1.30*10^{-3}C/m^3}{3(8.85*10^{-12}C^2/Nm^2)}((0.112m)-\frac{(0.10)^3}{(0.112m)^2})\\\\E=1,580,594.95\frac{N}{C}$

hence, the electric field is 1580594.95 N/C

7 0

2 years ago

A tennis player tosses a tennis ball straight up and then catches it after 2.07 s at the same height as the point of release.

prisoha [69]

(a) The ball will accelerate at a speed of 9.81 m/s² while it is in flight.

(b) The ball will be moving at a speed of 0 m/sec when it reaches its highest point.

(c) The ball's initial upward velocity is 20.30 m/s.

(d) It will reach a maximum height of 21.0 m.

<h3 /><h3>What is speed?</h3>

Speed is defined as the change in distance with regard to time. A scalar quantity, speed. It is a temporal element, m/sec is its unit.

The information provided in the issue is;

u is the fall's beginning speed in m/sec;

h is the fall's distance

g is the fall's acceleration or 9.81 m/sec²

a. The ball's speed while in flight is equal to the acceleration caused by gravity, which is 9.81 m/s².

b. When the ball reaches its highest point, its velocity will be zero.

c. The ball's starting velocity is;

v=u-gt

0=u-gt

u=gt

u=9.81 m/s² × 2.07 sec

u=20.30 m/s

d. The formula is used to determine the highest height it can reach.

$\rm u^2 = - 2gh \\\\ (20.30)^2 = -2 \times (-9.8) \times h \\\\ 412.09 = 19.6 \times h\\\\ h = 412.09/19.6\\\\ h = 21.00 m$

As a result, the ball's greatest height, beginning velocity, and acceleration are all 9.81 meters per second, zero meters per second, 20.30 meters per second, and 21 meters accordingly.

To learn more about the velocity, refer to the link: brainly.com/question/862972.

#SPJ1

3 0

2 years ago