Let
denote the rocket's position, velocity, and acceleration vectors at time
.
We're given its initial position

and velocity

Immediately after launch, the rocket is subject to gravity, so its acceleration is

where
.
a. We can obtain the velocity and position vectors by respectively integrating the acceleration and velocity functions. By the fundamental theorem of calculus,


(the integral of 0 is a constant, but it ultimately doesn't matter in this case)

and



b. The rocket stays in the air for as long as it takes until
, where
is the
-component of the position vector.

The range of the rocket is the distance between the rocket's final position and the origin (0, 0, 0):

c. The rocket reaches its maximum height when its vertical velocity (the
-component) is 0, at which point we have


Answer:
60 tokens/ 10 games?
Step-by-step explanation:
Answer:
10 inches
Step-by-step explanation:
Surface Area = π R² + π R L [ L is Slant Height ]
200 π = π (10)² + π (10) L
200 π = π (100) + π (10) L
200 π - 100 π = 10 π L
100 π = 10 π L
100 π / 10 π = L
10 = L
L = 10 inches
Hope this Helps......
Answer:
(0,1)- y intercept (1,0) x intercept
Step-by-step explanation:
first lets write this equation in slope intercept form: y=mx+b
m=slope
b=y intercept
so
slope formula:
(y2-y1)/(x2-x1)
y2=-3
y1=9
x2=4
x1=-8
so
(-3-9)/(4--8)=-12/12=-1
slope=-1
hence
y=-1x+b
substitute "x" as 4 and "y" as -3
so
-3=-1(4)+b
-3=-4+b
1=b
so
y=-x+1
1=y intercept
and
0=-x+1
-1=-x
1=x
1=x intercept