Check the picture below.
make sure your calculator is in Degree mode.
Ok let’s solve it
5(x-2)^2-20=0
first let’s foil (x-2)
5(x^2-4x+4) -20=0
now distribute the 5
5x^2 -20x +20 -20 = 0
combine like terms
5x^2-20x=0
take the gcf
5x(x-4)=0
x=0, 4
solutions are (4,0) and (2, -20) because the original vertex form a(x-h)^2+k
Answer:
i hated this math in middle school-
Step-by-step explanation:
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y(t) = a*e^(kt)</span><span>
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now:</span><span>
130 mg</span><span>
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one hour from intake:</span><span>
130 * (1 - 0.11) = 115.7 mg</span><span>
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y(1) = 115.7 = 130*e^(k(1))</span><span>
115.7 = 130*e^k</span><span>
115.7/130 = e^k</span><span>
ln( 115.7/130 ) = ln( e^k )</span><span>
ln( 115.7/130 ) = k</span><span>
k = -0.1165338
</span><span>---
three hours from intake:</span><span>
y(3) = 130*e^(3k)</span><span>
y(3) = 91.64597</span><span>
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answer:</span><span>
three hours after drinking a cup of coffee, 91.6 mg of caffeine will remain in the body
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