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kompoz [17]
3 years ago
12

What is the measure of the arc represented by the numbers 6 and 11 on a clock face?

Mathematics
2 answers:
Marat540 [252]3 years ago
8 0
150; because 6-11 is almost 180, but it’s not quite there, so it’s a little less
Solnce55 [7]3 years ago
4 0
The answer is to this is 150
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Which properties are used to prove that the expressions 5x+x-2 and 6x-2 are equivalent? 5x+x-2 (5+1)x-2 6x-2
sergeinik [125]

Answer:

Associative and Commutative properties

Step-by-step explanation:

7 0
2 years ago
The sum of 4 times a number and 7 more than the number is 80
marusya05 [52]

Answer:

(4×x) 7> 80  :)

Step-by-step explanation:

4 0
2 years ago
Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form
Alex787 [66]

Answer:

y=-\frac{2}{5}x-\frac{1}{5}

Step-by-step explanation:

The equation of a line is y = mx + b

Where:

  • m is the slope
  • b is the y-intercept

First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

m = -\frac{2}{5}

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=-\frac{2}{5}x + b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

  • (-3,1). When x of the line is -3, y of the line must be 1.
  • (2,-1). When x of the line is 2, y of the line must be -1.

Now, look at our line's equation so far: y=-\frac{2}{5}x + b. b is what we want, the --\frac{2}{5} is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

  • (-3,1). y = mx + b or 1=-\frac{2}{5} * -3 + b, or solving for b: b = 1-(-\frac{2}{5})(-3).b = -\frac{1}{5}.
  • (2,-1). y = mx + b or -1=-\frac{2}{5} * 2 + b, or solving for b: b = 1-(-\frac{2}{5})(2). b = -\frac{1}{5}.

See! In both cases, we got the same value for b. And this completes our problem.

The equation of the line that passes through the points  (-3,1) and (2,-1) is y=-\frac{2}{5}x-\frac{1}{5}

8 0
2 years ago
I need 20 characters to post this so ignore
Natali5045456 [20]
KSKDWKDKSODMEMFKSCK HHHHhhhHhHhHhHhhsenfjsockwmf
6 0
2 years ago
Will give they crownnnnn
Aleksandr [31]

Answer:

c 44

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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