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bezimeni [28]
3 years ago
10

Which of the following measurements has two significant digits?

Physics
2 answers:
myrzilka [38]3 years ago
7 0
0.022 has 2 digits because you would count from the left starting with the first nonzero number
Shkiper50 [21]3 years ago
3 0
0.022km explanation: 0.3g only has 1 sig digit and so does thy other ones except for 0.022
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Help please, what does gravitational force do according to these answer choices?
laiz [17]

Answer:

the answer is C

Explanation:

gravity forces down not up or sideways.

5 0
2 years ago
Tarzan (who has mass 80.0 kg) is running across the jungle floor with speed 7.00 m/s as
Lesechka [4]

<u>We are given:</u>

Mass of Tarzan before swinging = 80 kg

Mass of Tarzan when swinging = 80 + 15 = 95 kg

Velocity of Tarzan = 7 m/s

The height of the rock Tarzan's monkey is sitting on = 3 m

__________________________________________________________

<u>Momentum of Tarzan before swinging:</u>

We know that:

Momentum = Mass*Velocity

Momentum = 80 * 7

Momentum = 560 kg m/s

__________________________________________________________

<u>Speed of Tarzan after grabbing the bananas:</u>

The momentum of Tarzan will remain the same but his mass will increase

So, Since Momentum = New Mass* velocity

560 = 95 * v                           [where v is the velocity of Tarzan]

v = 5.9 m/s

<u>__________________________________________________________</u>

<h3><u>Finding the Initial and Final KE and PE:</u></h3>

<em>Here, KE = Kinetic Energy and PE = Potential Energy</em>

<u>Initial and Final KE:</u>

We know that KE = 1/2*(mv²)

<u>Initial KE:</u>

Initial KE = 1/2*(mv²)          [where v is the velocity after picking the bananas]

Initial KE = 1/2*(95*5.9²)

Initial KE = 1653.5 Joules

<u>Final KE:</u>

Final KE = 1/2*(mv²)            

<em>[where v is the velocity at the maximum point of the swing]</em>

Since Tarzan will be at rest at the maximum point of the swing, v = 0 m/s

Final KE = 1/2*(95*0²)

Final KE = 0 Joules

<u>Initial and Final PE:</u>

We know that:

PE = mgh                

<em>[where g is the acceleration due to gravity and h is the height]</em>

<u>Initial PE:</u>

Since the height of Tarzan from the ground was 0 m at the beginning of the swing, h = 0

Initial PE = 95*10*0

Initial PE = 0 Joules

<u>Final PE:</u>

Let the maximum height of Tarzan be h m

Final PE = 95*10*h

Final PE = 950(h)

__________________________________________________________

<h3><u>Finding the maximum height Tarzan will reach:</u></h3>

<em>Here, KE = Kinetic Energy and PE = Potential Energy</em>

From the law of conservation of momentum, we know that:

Initial KE + Initial PE = Final KE + Final PE

Replacing the variables:

1653.5 + 0 = 0 + 950h

1653.5 = 950h

h = 1653.5/950         [dividing both sides by 950]

h = 1.74 m

Therefore, the maximum height reached by Tarzan is 1.74 m

but since his monkey is sitting 3 m high, he will NOT be able to reach his monkey

6 0
2 years ago
A parallel RLC circuit contains an inductor with a value of 400 microhenries and a capacitor with a value of 0.3 microfarads wha
ipn [44]

Answer:

The resonant frequency of this circuit is 14.5 kHz.

Explanation:

Given that,

Inductance of a parallel LCR circuit, L=400\ \mu H=400\times 10^{-6}\ H

Capacitance of parallel LCR circuit, C=0.3\ \mu F=0.3\times 10^{-6}\ F

At resonance the inductive reactance becomes equal to the capacitive reactance. The resonant frequency is given by :

f=\dfrac{1}{2\pi \sqrt{LC} }

f=\dfrac{1}{2\pi \sqrt{400\times 10^{-6}\times 0.3\times 10^{-6}} }

f=14528.79\ Hz

or

f = 14.5 kHz

So, the resonant frequency of this circuit is 14.5 kHz. Hence, this is the required solution.

4 0
3 years ago
A basketball leaves a player's hands at a height of 2.00 m above the floor. The basket is 3.05 m above the floor. The player lik
shutvik [7]

Answer:(10.69, 11.436)

Explanation:

Given

initial height of ball is 2 m

height of basket is 3.05 m

Launching angle=40^{\circ}

x =12\pm 0.27

y=1.05

equation of trajectory of ball is given by

y=xtan\theta -\frac{gx^2}{2u^2cos^2\theta }

for x=12.27

1.05=12.27\times tan40-\frac{g12.27^2}{2u^2cos^{2}40 }

u=10.69

for x=11.73

1.05=11.73\times tan40-\frac{g11.73^2}{2u^2cos^{2}40 }

u=11.436 m/s

Thus range of speed is (10.69, 11.436)

3 0
2 years ago
What do organisms need in order to reproduce? This is Science Btw
Delicious77 [7]

Answer:

Energy. They need energy.

Explanation:

7 0
3 years ago
Read 2 more answers
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