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Ksenya-84 [330]
2 years ago
11

PLEASE HELP WILL MARK AS BRAINLIEST!!!

Physics
1 answer:
marta [7]2 years ago
5 0
The answer is a because tjhey do move at a molecular movemn
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A 3874-kg rollercoaster is brought to the top of a 42m hill in 40 seconds,then drops 28m before the next hill.
Ede4ka [16]

(a) The work required to get the coaster to the top of the first hill is  1,594,538.4 J.

(b) The power required to bring the train to the top of the first hill is 39,863.46 W.

(c) The energy lost when the coaster drops is 531,512.8 J.

(d) The left at the bottom is determined as 1,063,025.6 J.

<h3>Work done to bring the rollercoaster top of the hill</h3>

W = Fn x d = mgh

W = 3874 x 9.8 x 42

W = 1,594,538.4 J

<h3>Power dissipated in bringing the rollercoaster on top hill</h3>

P = Fv

P = Fd/t

P = W/t

P = 1,594,538.4 /40 = 39,863.46 W

<h3>Energy lost when the coaster drops</h3>

E = 1,594,538.4 - (3874 x 9.8 x 28)

E = 531,512.8 J

<h3>Energy left at the bottom</h3>

E = 3874 x 9.8 x 28 = 1,063,025.6 J

Learn more about energy here: brainly.com/question/13881533

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6 0
2 years ago
The exosphere is the layer of the atmosphere
gayaneshka [121]
The exosphere is the layer of the atmosphere "Where gas molecules can be exchanged between Earth's atmosphere and outer space." Thus, the answer would be C.
8 0
3 years ago
Read 2 more answers
A string is wound around a uniform disc of radius 0.68 m and mass 3.7 kg. The disc is released from rest with the string vertica
Zolol [24]

Answer:

3.962

Explanation:

mass = 1.2

gravity g = 9.81

velocity = ?

mgh = 1/2mv² + 1/2(1/2)mv²

= 9.81 x 1.2  = 3/4v²

11.772 x 4 = 3/4v²

47.088 = 3v²

divide through both sides by 3

15.696 = v²

take the square root of both sides

√15.696 = √v²

= 3.6962 = v

the speed is therefore 3.692

8 0
2 years ago
A bowling ball weighing 71.2 N is attached to the ceiling by a 3.30 m rope. The ball is pulled to one side and released; it then
wolverine [178]

Answer:

a. The acceleration of the bowling ball is 9.5 m/s² toward the center

b.  The tension in the rope is 140.24 N

Explanation:

given information:

ball weight,  W = 71.2 N

the length of rope, R = 3.30 m

ball speed, v = 5.60 m/s

a. The acceleration of the bowling ball, α

α = \frac{v^{2} }{R}

where

α = the acceleration

v = the speed

R = radius

thus

α = \frac{v^{2} }{R}

  = \frac{5.60^{2} }{3.3}

  = 9.5 m/s² toward the center

b. The tension in the rope?

according to the Newton's second law

ΣF = m a

where

F = force

m = mass

a = acceleration

so,

ΣF = m a

T - W = m a

T = m a + W

  = (W a/g) + W

  = (71.2 x 9.5/9.8) + 71.2

  = 140.24 N

4 0
2 years ago
E = 1 × 4 × (40 - 20)
tankabanditka [31]

Answer:

80

Explanation:

1 x 4 = 4

40- 20 = 20

so... 4 x 20 = 80

5 0
3 years ago
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