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Vedmedyk [2.9K]
3 years ago
5

John is traveling north at 20 meters/second and his friend Betty is traveling south at 20 meters/second. If north is the positiv

e direction, what are John and Betty's speeds? A. -20 meters/second, 20 meters/second B. 20 meters/second, 20 meters/second C. -20 meters/second, -20 meters/second D. 0 meters/second, 40 meters/second
Physics
2 answers:
soldier1979 [14.2K]3 years ago
8 0
The answer is definitely A
rewona [7]3 years ago
7 0

Answer:

B. 20 meters/second, 20 meters/second

Explanation:

Velocity of John = 20 meters/second north = +20 meters/second

Velocity of Betty =  20 meters/second south = -20 meters/second

If north is considered as positive then south will be negative.

So, the velocity of John will be +20 meters/second and velocity of Betty will be -20 meters/second.

But, the question is about their speeds and not velocity. The signs represent the directions. Speed does not show direction.

So, speed of John and Betty is 20 meters/second.

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Hi there!

Using Newton´s second law, we can calculate the deceleration:

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