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3 years ago

What is the name for the clockwise deflection of air in the cells near the poles?

1 answer:

4 0

The clockwise deflection of air in the cells near the poles is called polar circulation (It also called an air circulation or an atmospheric circulation). It is a system of winds by which the necessary transport of heat from tropical to polar latitudes is accomplished. The circulation cell closest to the equator is called the Hadley cell (between 30 and 40 degrees north and south). Ferell cells are the middle cells (60 and 70 degrees north and south).Polar cells are the smallest and weakest cells (from between 60 and 70 degrees north and south, to the poles).

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A cube of side 6.50 cm is placed in a uniform field E = 7.50 × 10^3 N/C with edges parallel to the field lines (field enters the

Svetllana [295]

Answer:

a) $\Phi_{net} = 0\,\frac{N\cdot m^{2}}{C}$ , b) $\Phi_{right} = -31.688\,\frac{N\cdot m^{2}}{C}$ , c) $\Phi_{left} = 31.688\,\frac{N\cdot m^{2}}{C}$

Explanation:

a) The net flux through the cube is:

$\Phi_{net}=-(7.50\cdot 10^{3}\,\frac{N}{C} )\cdot (0.065\,m)^{2}+(7.50\cdot 10^{3}\,\frac{N}{C} )\cdot (0.065\,m)^{2}$

$\Phi_{net} = 0\,\frac{N\cdot m^{2}}{C}$

b) The flux through the right face is:

$\Phi_{right}=-(7.50\cdot 10^{3}\,\frac{N}{C} )\cdot (0.065\,m)^{2}$

$\Phi_{right} = -31.688\,\frac{N\cdot m^{2}}{C}$

c) The flux through the left face is:

$\Phi_{left}=(7.50\cdot 10^{3}\,\frac{N}{C} )\cdot (0.065\,m)^{2}$

$\Phi_{left} = 31.688\,\frac{N\cdot m^{2}}{C}$

5 0

3 years ago

Read 2 more answers

What is the difference between an elastic and inelastic collision

barxatty [35]

Answer:

In an elastic collision, the total kinetic energy is conserved, while in an inelastic collision, it is not

Explanation:

Let's define the two types of collision:

- Elastic collision: an elastic collision is a collision in which:

1) the total momentum of the system is conserved

2) the total kinetic energy of the system is conserved

Typically, elastic collisions occur when there are no frictional forces acting on the objects in the system, so that no kinetic energy is lost into thermal energy. An example of elastic collision is the collision between biliard balls.

- Inelastic collision: an inelastic collision is a collision in which:

1 ) the total momentum of the system is conserved

2) the total kinetic energy of the system is NOT conserved

In an elastic collision, part of the total kinetic energy is lost (=converted into thermal energy) due to the presence of frictional forces. An example of inelastic collision is the accident between two cars, in which part of the energy is converted into heat.

4 0

4 years ago

For a huge luxury liner to move with constant velocity, its engines need to supply a forward thrust of 6.85 105 N. What is the m

Leviafan [203]

Answer:

The magnitude of the resistive force exerted by the water is $6.85\times 10^{5}$ newtons.

Explanation:

By First and Second Newton's Law, the resistive force exerted by the water on the cruise ship has the same magnitude of forward thrust, with which it is antiparallel to. The equation of equilibrium for the luxury liner is:

$\Sigma F = F-R = 0$ (Eq. 1)

Where:

$F$ - Forward trust, measured in newtons.

$R$ - Resistive force exerted by the water, measured in newtons.

From (Eq. 1), we get that: ( $F = 6.85\times 10^{5}\,N$ )

$R = F$

$R = 6.85\times 10^{5}\,N$

The magnitude of the resistive force exerted by the water is $6.85\times 10^{5}$ newtons.

4 0

3 years ago

Can sumbody help me wit dis

stepladder [879]

C, exothermic reaction. These types of reaction releases heat so that you can heat up your ready-to-eat meals.

3 0

3 years ago

Three equal point charges, each with charge 1.15 μCμC , are placed at the vertices of an equilateral triangle whose sides are of

julsineya [31]

Answer:

$U=50.96J$

Explanation:

The electrostatic potential energy for pair of charge is given by

U=1/4π∈₀×(q₁q₂/r)

Hence for a system of three charges the electrostatic potential energy can be found by adding up the potential energy for all possible pairs or charges.For three equal charges on the corners of an equilateral triangle,the electrostatic potential energy is given by:

U=1/4π∈₀×(q²/r)+1/4π∈₀×(q²/r)+1/4π∈₀×(q²/r)

U=3×1/4π∈₀×(q²/r)

Substitute given values

$U=3\frac{1}{4\pi E_{o} }\frac{q^{2} }{r}\\ U=3\frac{1}{4\pi8.85*10^{-12} }\frac{(1.15*10^{-6}C )^{2} }{0.0007m}\\ U=50.96J$

8 0

3 years ago