I’m here to help.
For this question here you need to use the sine formula for the area of a triangle and figure out the area of the sector
I’ll take you through it step-by-step
Area of the arc:
We only have 68.9 degrees out of 360 and we need to use the formula for the area of a circle.
Formula of a circle = pi x radius squared
68.9/360 x pi x 86.1184= 51.78 (2dp)
Area of triangle:
As you can see we have no height so we must use the sine formula for the area of a triangle.
Formula= 1/2abSinC
You should end up with
0.5 x 9.28x 9.28 x Sin(68.9)= 40.17 (2dp)
Now since you want the area of the segment shaded, just find the difference between these two values.
51.78-40.17 = 11.61
Answer= 11.6cm squared
Hope this helped!
Answer:
x/2+9=-15
Step-by-step explanation:
Answer:
y=-1/2x+-1
Step-by-step explanation:
try desmos with this equation.
y=mx+b
m=the slope which is -1/2. It goes down 1 it is negative because it is going down, and to the right 2.
b=y-intercept meaning the point which the line crosses the line y .-1
In this case, to prove what is required, we must use the Pythagorean theorem to find the diagonal of the square.
If the diagonal of the square is smaller than the diameter of the circle, then the square will fit perfectly in the circle without touching it.
Diagonal = Root ((7 ^ 2) + (7 ^ 2)) = 9.89 cm.
we observed that
9.89cm <11cm.
Therefore we show that:
the square will fit inside the circle without touching the edge of the circle
