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sergey [27]
3 years ago
12

There are 800 students in a high school. Two-fifths of the students are freshman, and 3/4 of the upperclassmen (sophomores thru

seniors) are involved in an enrichment. How many upperclassmen are not involved in an enrichment?
Mathematics
1 answer:
Vlada [557]3 years ago
6 0

Answer:

1/4 upperclassmen are not involved in enrichment.

Step-by-step explanation:

"3/4 of the upperclassmen (sophomores thru seniors) are involved in an enrichment." That leaves 1/4 upperclassmen students left. Verification: 3/4 + 1/4 = 4/4. 4/4 is also 1 whole.

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Answer:

7 inches

Step-by-step explanation:

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2 years ago
37.
zimovet [89]

Answer:

  • 15

Step-by-step explanation:

<u>There are total cadies in the bag:</u>

  • 7 + 13 + 5 = 25

<u>Probability of pulling a coffee candy is:</u>

  • 5/25 = 1/5

So each 5th candy should be coffee candy

<u>Then you need to pull at least:</u>

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<em><u>Note:</u></em>

<em><u>To ensure 3 coffee candies you would need to pull 25 - 2 = 23 candies</u></em>

5 0
2 years ago
Given the equation y − 3 = one half(x + 6) in point-slope form, identify the equation of the same line in standard form.
Schach [20]

Answer:

A. x-2y=-12

Step-by-step explanation:

We have been given an equation of a line in point-slope form. We are asked to write our given equation in standard form.

y-3=\frac{1}{2}(x+6)

Since we know that standard form of equation is: ax+by=c, where, a, b and c are constants.

Let us multiply both sides of our given equation by 2.

(y-3)*2=2*\frac{1}{2}(x+6)

2y-6=x+6

Let us add 6 to both sides of our equation.

2y-6+6=x+6+6

2y=x+12

Let us subtract x from both sides of our equation.

2y-x=x-x+12

2y-x=12

Multiply both sides of our equation by -1.

-2y+x=-12

Rearranging our equation we will get,

x-2y=-12

Therefore, the standard form of our given equation is x-2y=-12 and option A is the correct choice.

4 0
3 years ago
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7 0
2 years ago
Read 2 more answers
Choose the correct answer below.
Elodia [21]

Answer:

c

Step-by-step explanation:

3 0
3 years ago
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