Answer:
(d) f(x) = -x²
Step-by-step explanation:
For the vertex of the quadratic function to be at the origin, both the x-term and the constant must be zero. That is, the function must be of the form ...
f(x) = a(x -h)² +k . . . . . . . . . . vertex form; vertex at (h, k)
f(x) = a(x -0)² +0 = ax² . . . . . vertex at the origin, (h, k) = (0, 0)
Of the offered answer choices, the only one with a vertex at the origin is ...
f(x) = -x² . . . . . a=-1
Step-by-step explanation:
i think 48888 because i think so and you do to
Answer:
c and d
Step-by-step explanation:
Answer:
Step-by-step explanation:
slope of -2 means the slope is -2/1
from (3, - 8) you can find the y intercept by going backwords until x = 0
(2,-6)
(1,-4)
(0,-2)
so the y intercept is -2
y = -2x - 2
Step-by-step explanation:
I think no. c is correct
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