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2 years ago

How are percent diagrams used to solve real-world problems

Mathematics

2 answers:

ddd [48]2 years ago

4 0

Answer:

Percent diagram helps to display information, making it easier to solve for what is missing.

A diagram is a way to help your brain process a lot of information at once. It is a visual planning tool that takes some of the pressure off of remembering every single detail. Sometimes we have hard questions that require sifting through a lot of information to figure them out.

<em>This type of chart or diagram gives a quick, easy way to see how a whole is divided into its constituent parts.</em>

fgiga [73]2 years ago

3 0

<span>One fourth of the students in Mrs. Singh’s music class chose a guitar as their favorite musical instrument. There are 24 students in Mrs. Singh’s music class. How many students chose a guitar as their favorite musical instrument? There are students in Mrs. Singh’s music class. Divide the number of students equally into 4 sections. Fill in the number in each section students % ---- %--- So, students chose guitar as their favorite musical instrument. </span>

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Can someone explain how to even do this, I literally just don't get it

kolezko [41]

Answer:

It is an isosceles triangle (side FE = FG)

Therefore the base angles are equal.

75 degrees = 2x degrees

x = 75 / 2 = 37.5 degrees

Step-by-step explanation:

3 0

2 years ago

The exact value of cos5pi/12 is:

jonny [76]

Step 1: Convert $\frac{5\pi }{12}$ , which is in radians into degrees. To convert it multiply by $\frac{180}{\pi }$

$\frac{5\pi }{12} =\frac{180}{\pi }$

900/12

Step 2: 75 degrees isn't on the unit circle but 45 degrees and 30 degrees is. Since 45 + 30 = 75 you can use the cosine of 45 and 30 to find the exact value

cos45 = $\frac{\sqrt{2} }{2}$

cos30 = $\frac{\sqrt{3} }{2}$

Step 3: Add the cos45 and cos30 to get cos5pi/12

$\frac{\sqrt{2} }{2} +\frac{\sqrt{3} }{2} = \frac{\sqrt{2}+\sqrt{3}}{2}$

Hope this helped!

4 0

2 years ago

Caden states that n^2 +3n + 2n is an equivalent expression to 6n. Why is Caden's statement incorrect?

malfutka [58]

$\begin{gathered} \text{The simplification of n}^2+3n+2n\text{ is:} \\ i)n^2+5n \\ By\text{ collecting common term, this can be written in form of:} \\ ii)\text{ n(n+5)} \end{gathered}$

Thus, options A and D hold, from the simplifications above.

Let's consider the validity of the remaining options provided.

$\begin{gathered} \text{For option B)} \\ \text{substitute for n=1 into the expression n}^2+3n+2n,\text{ we have} \\ 1^2+3(1)+2(1)=1+3+2=6 \\ \text{substitute for n=1 into the expression 6n, we have} \\ 6(1)=6 \\ \text{Thus, the expression n}^2+3n+2n\text{ is equivalent to 6n, for n=1} \end{gathered}$ $\begin{gathered} \text{For option C)} \\ \text{The expression n}^2+3n+2n\text{ does not simplify to 7n} \end{gathered}$ $\begin{gathered} \text{For option E)} \\ \text{substitute for n=4 into the expression n}^2+3n+2n,\text{ we have:} \\ 4^2+3(4)+2(4)=16+12+8=36 \\ \text{substitute for n=6 into the expression 6n, we have:} \\ 6(4)=24 \\ \text{Thus, the two(2) expressions are not equivalent to each other, for n=4} \end{gathered}$ $\begin{gathered} \text{For option F)} \\ \text{substitute for n=3 into the expression n}^2+3n+2n,\text{ we have:} \\ 3^2+3(3)+2(3)=9+9+6=24 \\ \text{substitute for n=3 into the expression 6n, we have:} \\ 6(3)=18 \\ \text{Thus, the two(2) expressions are not equivalent to each other, for n=3} \end{gathered}$

Hence, the correct options that apply are options A, D, E and F

7 0

7 months ago

A book sold 31,100 copies in its first month of release. Suppose this represents 7.8% of the number of copies sold to date. How

zvonat [6]

For this problem you can create a proportion.
Since 31,100 copies is 7.8% of the total copies spoke up to date you can make this proportion:
31,100. 7.8%
——— =. ———
x. 100%
Now you cross multiply and you will get
7.8x=3,110,000
After this you solve for x by isolating the variable.
7.8x/7.8. 3,110,000/7.8
x=398,717.949
Since the question asks you to round to the nearest whole number which is 7 then the final answer would be 398,718
Answer: There has been 398,718 copies sold to date.

5 0

3 years ago

Simplify. Your answer should contain only positive exponents with no fractional exponents in the denominator.

mart [117]

Answer:

$\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$ .

Step-by-step explanation:

The given expression is

$\dfrac{3y^{\frac{1}{4}}}{4x^{-\frac{2}{3}}y^{\frac{3}{2}}\cdot 3y^{\frac{1}{2}}}$

We need to simplify the expression such that answer should contain only positive exponents with no fractional exponents in the denominator.

Using properties of exponents, we get

$\dfrac{3}{4\cdot 3}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{\frac{3}{2}+\frac{1}{2}}}$ $[\because a^ma^n=a^{m+n}]$

$\dfrac{1}{4}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{2}}$

$\dfrac{1}{4}\cdot \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{y^{2}}$ $[\because a^{-n}=\dfrac{1}{a^n}]$

$\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$

We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.

Therefore, the required expression is $\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$ .

5 0

3 years ago