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rewona [7]
4 years ago
9

Use the line graph to solve.

Mathematics
1 answer:
Ksenya-84 [330]4 years ago
4 0
The answer is c. 0.10. Week 4 is plotted at 0.35 and Week 2 is plotted at 0.25. Difference means subtract. 0.35 - 0.25 = 0.10. Hope this helps!
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25 points please help me!
lianna [129]
$1.14   1.40 x 0.8=1.12 1.4+ 1.12=1.52 * 0.25 = 1.14
8 0
3 years ago
Graph the function f(x)=−13x+1.
pogonyaev

Graph each points:

f(x) = -13x + 1

when x = 0, y = 1

f(0) = -13(0) + 1

f(0) = 0 + 1

f(0) = 1

when x = 1, y = -14

f(1) = -13(1) + 1

f(1) = -13 + 1

f(1) = -14

when x = 2, y = -25

f(2) = -13(2) + 1

f(2) = -26 + 1

f(2) = -25

etc.

Graph each point and connect them.

7 0
3 years ago
Estimate 0.067238149 to the nearest hundredth. Express your answer as a single digit times a
Maurinko [17]

Answer:

0.07

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Use the Law of Sines to find the length of AC
ddd [48]
<h3>Answer:  30.78181 meters</h3>

The value is approximate. Round that however you need to.

========================================================

Explanation:

  • lowercase a = side opposite angle uppercase A
  • lowercase b = side opposite angle uppercase B
  • b = AC

Using the law of sines, we can say:

a/sin(A) = b/sin(B)

45/sin(30) = b/sin(20)

b/sin(20) = 45/sin(30)

b = sin(20)*45/sin(30)

b = 30.78181 approximately

You'll need to make sure your calculator is in degree mode.

3 0
3 years ago
Find the PERIMETER of this triangle
olga2289 [7]
First we need to find the missing side, use

a =  \sqrt{ {c}^{2} -  {b}^{2}  }
So the missing leg = the sqrt of the hypotenuse squared minus the other leg squared.

Let's substitute the numbers,

a =  \sqrt{ {10}^{2}  -  {6}^{2} }
Solve for the squares,

a =  \sqrt{100 - 36}
Subtract,

a =  \sqrt{64}
Solve for the root,

a = 8
~~

So our missing length is 8.

To find the perimeter of the triangle, simply add all the sides....

~~

8 + 10 + 6 = 24

~~

Answer : 24

~~

I hope that helps you out!!

Any more questions, please feel free to ask me and I will gladly help you out!!

~Zoey
4 0
3 years ago
Read 2 more answers
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