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3 years ago

I'm taking the ACT Saturday what calculators are permitted

Mathematics

2 answers:

Ber [7]3 years ago

8 0

If your in 11th grade, I believe any handheld calculators.

Leno4ka [110]3 years ago

3 0

This is from the act site
I googled "act approved calculators list" and clicked on the act.org link

any calculator that can't do algebra is good
so scientific or four function calculators (the cheap ones) are good
some graphing calculators are banned

it's easier to find te ones that are banned
TI-89 and higher is not allowed
TI-Nspire CAS is banned
calculators that have "computer algebra system functionality" are banned (you can't use a calculator that can solve for x for you)
calculators can't have QUERTY keyboard layout
calculators can't have pen input

can't use Hewlett-Packard Prime, or Hewlett-Packard48Gll or any Hewlett-Packard with model number beginning with HP40G, HP49G, or HP50G

you can't use these casio calculators
fx-CP400 (ClassPad 400)ClassPad 300ClassPad 330Algebra fx 2.0All model numbers that begin with CFX-9970G

make sure you bring extra bateries and know how to use your calculator
make sure it doesn't make noises or distract other people as well

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1. Solve for w in the equation W/5 = 25 A.W = 5 B.W = 125 C. W = 30 D.W = 20

vekshin1

Answer: w = 125

Explanation: Since w is being divided by 5, to solve for w,

multiply both sides of the equation by 5.

On the left side, the 5's will cancel

and on the right side, 25(5) is 125.

So w = 125.

Please do not do this problem in your head.

Show the work that it takes to get w by itself.

3 0

3 years ago

Delaney would like to make a 5 lb nut mixture that is 60% peanuts and 40% almonds. She has several pounds of peanuts and several

jonny [76]

A) A ratio system

B) The 4 lb peanuts and the 1 lb mixture because the 4lb added to the 1lb of mixture give the correct percentages.

4 0

3 years ago

Hi! ❤️ I’m looking for help here thanks.

abruzzese [7]

Answer:

i dont remember how to do this and i just did this last year

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The paint used to make lines on roads must reflect enough light to be clearly visible at night. Let µ denote the true average re

Zolol [24]

Answer:

a) $df=n-1=16-1=15$

The statistic calculated is given by t=3.3

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}>3.3)=0.0024$

So since the p value is lower than the significance level $pv$ we reject the null hypothesis.

b) $df=n-1=8-1=7$

The statistic calculated is given by t=1.8

Since is a one-side upper test the p value would be:

$p_v =P(t_{7}>1.8)=0.057$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

c) $df=n-1=26-1=25$

The statistic calculated is given by t=-0.6

Since is a one-side upper test the p value would be:

$p_v =P(t_{25}>-0.6)=0.723$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation

$\bar X$ represent the sample mean

$s$ represent the standard deviation for the sample

$n$ sample size

$\mu_o =20$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the true mean is higher than 20, the system of hypothesis would be:

Null hypothesis: $\mu \leq 20$

Alternative hypothesis: $\mu > 20$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

(a) n = 16, t = 3.3, a = 0.05, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=16-1=15$

The statistic calculated is given by t=3.3

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}>3.3)=0.0024$

So since the p value is lower than the significance level $pv$ we reject the null hypothesis.

(b) n = 8, t = 1.8, a = 0.01, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=8-1=7$

The statistic calculated is given by t=1.8

Since is a one-side upper test the p value would be:

$p_v =P(t_{7}>1.8)=0.057$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

(c) n = 26,t = -0.6, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=26-1=25$

The statistic calculated is given by t=-0.6

Since is a one-side upper test the p value would be:

$p_v =P(t_{25}>-0.6)=0.723$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

3 0

4 years ago

A parallelogram with an area of 60 square units is formed by four lines in a coordinate plane. The parallelogram has one vertex

Alika [10]

Answer:

The answer above is wrong, the line is actually supposed to be one to the left, so it would be going through (7,4) and (2,-2)

Step-by-step explanation:

8 0

3 years ago