Answer:
When we have something like:
![\sqrt[n]{x}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D)
It is called the n-th root of x.
Where x is called the radicand, and n is called the index.
Then the term:
![\sqrt[4]{16}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16%7D)
is called the fourth root of 16.
And in this case, we can see that the index is 4, and the radicand is 16.
At the end, we have the question: what is the 4th root of 16?
this is:
![\sqrt[4]{16} = \sqrt[4]{4*4} = \sqrt[4]{2*2*2*2} = 2](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16%7D%20%3D%20%5Csqrt%5B4%5D%7B4%2A4%7D%20%20%3D%20%5Csqrt%5B4%5D%7B2%2A2%2A2%2A2%7D%20%3D%202)
The 4th root of 16 is equal to 2.
A dilation would produce<span> a </span>similar figure. Therefore, the sequence of transformations that will produce a similar but not congruent figures would be the first and the third option. Figure TUVWX is dilated by a scale factor of 6 and then rotated 90° counterclockwise around the origin; and f<span>igure TUVWX is reflected across the x-axis and dilated by a scale factor of 7. Hope this answers your question.</span>
That's the beginning of Euler's number ' e '.
It falls between the square roots of 7 and 8 .
Hey ! You know what !
It falls between the square roots of any integer
less than 8 and any integer greater than 7 .
The answer is 70.
5 + 2 = 7
7 x 10 = 70
Slope-intercept form is y=mx+b
m is slope and b is y-intercept.
So, if you have -5x-3y=3
Make it into y=something
So, -3y=3+5x
y= -3/3 + 5/-3 x
y= -1 - 5/3 x
Same as the first one in your pic.
