Give me an atom with the following characteristics.

Chemistry

2 answers:

Alex777 [14]3 years ago

8 0

Answer:

a. Halogen = an atom of Fluorine with chemical symbol F.

b. Alkali metal = an atom of Sodium with chemical symbol Na.

c. Noble gas = an atom of Argon with chemical symbol Ar.

d. Transition element = an atom of Copper with chemical symbol Cu.

e. Non metals = an atom of Oxygen with chemical symbol O.

Explanation:

a. Halogens are the family of chemical elements found in the group VIIA of the periodic table which means they possess seven (7) outer electrons e.g Fluorine (F), Chlorine (Cl).

b. Alkali metals are any of the monovalent elements found in Group IA of the periodic table. They readily lose their one valence electron to form ionic compounds with nonmetals. Examples of alkali metal are Lithium (L), Sodium (Na).

c. Noble gas are the gaseous elements occupying the group 0 of the periodic table e.g Neon Ne, Argon Ar.

d. A transition metal is one which forms one or more stable ions which have incompletely filled d orbitals e.g Scandium Sc, Copper Cu.

e. Non metals are elements that generally lacks metallic characteristic properties. They usually have high ionization energy and electronegativity e.g Carbon C, Oxygen O.

Novosadov [1.4K]3 years ago

5 0

A. Fluorine
b. Sodium
c. Helium
d. Copper
e. Oxygen

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In water solution, the conjugate base of HF is __________

anastassius [24]

Answer:

The correct answer is : $F^-$

Explanation:

According to the Bronsted Lowry conjugate acid-base theory, an acid is defined as a substance which donates protons and a base is defined as a substance which accepts protons.

Acid after donating protons changes into conjugate base and base after accepting protons changes into conjugate acid.

So, when HF in water reacts, it form fluoride ions and hydronium ions. The recation is given as:

$HF+H_2O\rightarrow F^-+H_3O^+$

Here, HF is acting as a Bronsted Lowry acid by donating proton and forms it conjugate base $F^-$ , Where as water is acting as a Bronsted Lowry base by accepting a proton and forms its conjugate acid $H_3O^+$ .