Answer:
The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

Step-by-step explanation:
<u>Explanation:</u>-
<u>Step 1:</u>-
The equation of the circle having center and radius is

here center is (h,k) and radius is r
Given diameter whose end points are (-1,-2) and (-3,2)
The diameter of the circle is passing through the center of the circle
so center of the circle = midpoint of two end points


therefore center (h,k) = (-2,0)
<u>Step 2:-</u>
we have to find the radius of the circle
the radius of the circle = the distance from center to the one end point
i.e., C P = r
Given one end point is P(-3,2) and center C(-2,0)
The distance formula of two points are



<u>Step 3</u>:-
center (h,k) = (-2,0) and
radius 
The standard form of circle equation


on simplification is
