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Usimov [2.4K]
4 years ago
5

A tornado lifts a truck 252 m above the ground. As the storm continues, the tornado throws the truck horizontally. It lands 560

m away from where it was picked up.
How fast was the truck traveling horizontally through its flight? Round your answer to the nearest tenth.
Physics
2 answers:
laiz [17]4 years ago
8 0

..................78.1

Mariulka [41]4 years ago
4 0

Answer:  78.1

Explanation:  Answer accurate on the assignment on line.

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IP address then call the cops
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3 years ago
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How much work is done when you push a crate horizontally with 150 N across a 13-m floor
Mila [183]
Work = (force) x (distance)

When a force of 150 N pushes through a distance of 13 meters,
it does

             Work = (150 N) x (13 m) = 1,950 joules .
6 0
4 years ago
¡¡first convert revolutions per second to
katovenus [111]

Answer:

a. 5.23 m/s² b. 44.23 N

Explanation:

a. What is the centripetal acceleration of the  hammer?  

The centripetal acceleration a = rω² where r = radius of circle and ω = angular speed.

Now r = length of chain = 1.4 m and ω = 0.595 rev/s = 0.595 × 2π/s = 3.74 rad/s.

So a = rω²

= 1.4 m × (3.74 rad/s)²

= 5.23 m/s²

b. What is the tension in the chain?

The tension in the chain, T = ma where m = mass of hammer = 8.45 kg and a = centripetal acceleration of hammer = 5.23 m/s². This tension is the centripetal force on the hammer.

So, T = 8.45 kg × 5.23 m/s²

= 44.23 N

6 0
3 years ago
Manny walked a total of 3 miles. The reference point used to calculate the total distance that he walked was the same as the end
yawa3891 [41]

Correct question:

Manny walked a total of 3 miles. The reference point used to calculate the total distance that he walked was the same as the ending point. Which describes where Manny most likely walked?

a. from the bottom of a hill to the top

b. on a circular nature trail

c. on a sidewalk from his house to the mall

d. from the beginning of a straight track to the end

Answer:

b. on a circular nature trail

Explanation:

As it is mentioned that Manny that his reference point from where she started is same as ending point meaning that she moved in a circular path making point B correct answer.

7 0
3 years ago
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You place an object 30.0 cm from a concave mirror of 15.0 cm focal length. The object is 1.8 cm tall. Find the image position an
Softa [21]

Answer:30 cm

Explanation:

Given

object distance u=30\ cm

focal length of concave mirror f=15\ cm

height of object h_o=1.8\ cm

Using mirror formula

\Rightarrow \frac{1}{v}+\frac{1}{u}=\frac{1}{f}

\Rightarrow \frac{1}{v}=\frac{1}{15}-\frac{1}{30}

\Rightarrow \frac{1}{v}=\frac{2-1}{30}

\Rightarrow v=30\ cm

and magnification is

\Rightarrow m=\frac{-v}{u}=\frac{h_i}{h_o}

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\Rightarrow h_i=-1.8\ cm

So height of object is same as of object .

Position :image is formed at the spot where object is placed.

4 0
3 years ago
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