All categories

4 years ago

Question 1 (1 point)

Physics

2 answers:

Dmitry [639]4 years ago

6 0

1). trajectory

2). person sitting in a chair

3). 490 meters

4). 65 m/s

5). False. The projectile's displacement, velocity, and acceleration have vertical and horizontal components, but the projectile doesn't.

6). False

7). The vertical component of a projectile doesn't change due to gravity, but the vertical components of its displacement, velocity, and acceleration do.

The vertical components do NOT equal the horizontal components.

8). Decreasing if you include the effects of air resistance. Constant if you don't. Gravity has no effect on horizontal velocity.

9). We can't see the simulation. But if the projectile doesn't have jets on it, then as it travels upward, its vertical velocity must decrease, because gravity is trying to not let it get away.

10). We can't see the simulation. But if the projectile is traveling downward, we would call that "falling", and its vertical velocity must increase, because gravity is pulling it downward.

Ksenya-84 [330]4 years ago

6 0

<h2>Answer 1: </h2>

<u> The path a projectile takes is known as the Trajectory </u>

<h2> Explanation: </h2>

Trajectory is the curved path that an object follows when it travels in space. It has two components x and y. X shows the range while y shows the height

<h2>Question 2 </h2>

<u> The odd choice is A person sitting in a chair, not moving</u>

<h2>Explanation: </h2>

As the name suggests, projectile motion is a type of motion. The person sitting in a chair is not moving and he is in rest so he cannot be taken into motion category.

<h2>Question 3 </h2>

<u>490 meters</u>

<h2>Explanation: </h2>

According to second equation of motion

S= vit + ½ gt²

Putting the values

S = 0 + ½ (9.8) (10)

S = 490 meters

<h2>Question 4 </h2>

<h2>Explanation: </h2>

As we know that

Speed = Distance / Time

So putting the values

Speed = 650 / 10

Speed = 65 m/s

<h2>Answer 5:</h2>

<u>The statement is true </u>

<h2>Explanation: </h2>

A projectile motion is composed of two components. X component is responsible for showing the range and Y component is responsible for the height of the projectile.

<h2>Answer 6</h2>

<u>The given statement is false </u>

<h2>Explanation: </h2>

The shape of projectile graph is a parabola, not an ellipse. The equatuion of a projectile gives us two values because it is a quadratic equation so that is why this type of motion gives parabola and not an ellipse.

<h2>Answer 7:</h2>

<u>The vertical component always equals the horizontal component. </u>

<h2>Explanation: </h2>

The horizontal component of a projectile is X and it is constant which means no force is acting on it whereas y component has a force of gravity so both of these components can never be the same.

<h2>Answer 8: </h2>

<u>During the course of trajectory, the horizontal component of the velocity is constant </u>

<h2>Explanation: </h2>

The horizontal component of trajectory is the X component. This component does not have any force upon it except the force of friction of earth and object. The friction force is also acting in x axis that is why we can say that during the course of trajectory, the horizontal component of the velocity is constant .

<h2>Answer 9 </h2>

<u> In the simulation above, as the projectile travels upward,its vertical velocity decreases </u>

<h2>Explanation: </h2>

Whenever an object moves against the force of gravity, it’s acceleration and velocity decreases because the gravitational pull tends the object to stay it on earth surface.

<h2>Answer :10 </h2>

<u> In the simulation above, as the projectile travels downward, the vertical velocity increases </u>

<h2>Explanation: </h2>

As the body comes towards the earth the gravitational acceleration increases with the rate of 9.8m/s². This acceleration is taken as positive and when the projectile hits the ground it is in its maximum speed.

You might be interested in

While driving, your car has an initial position of 3.2 m, an initial velocity of -8.4 m/s, and

KIM [24]

Answer:

The position of the car at t = 1.5 s is at -8.1625 meters

Explanation:

The initial position of the car is 3.2 meters

The initial velocity is -8.4 m/s

The constant acceleration is 1.1 m/s²

We need to find the final position of the car at the time t = 1.5 seconds

The displacement <em>s</em> = final position - initial position

$s=ut+\frac{1}{2}at^{2}$ , where <em>u</em> is the initial velocity, <em>a</em> is the

constant acceleration and <em>t</em> is the time

So we can find the final velocity by using the rule:

final position - initial position = $ut+\frac{1}{2}at^{2}$

initial position = 3.2 meters , u = -8.4 m/s , a = 1.1 ²m/s , t = 1.5 s

Substitute these values in the rule

final position - 3.2 = $(-8.4)(1.5)+\frac{1}{2}(1.1)(1.5)^{2}$

final position - 3.2 = -12.6 + 1.2375

final position - 3.2 = -11.3625

add 3.2 for both sides

final position = -8.1625

<em>That means the car is at 8.1625 meters in opposite direction</em>

<em>The position of the car at t = 1.5 s is at -8.1625 meters </em>

4 0

4 years ago

Rube goldberg machine steps

tankabanditka [31]

Answer:

Rube Goldberg Machine is "a comically involved, complicated invention, laboriously contrived to preform a simple operation." 2. What are the 6 Simple Machines? A. The 6 Simple Machines are: wedge, screw, lever, wheel and axel, inclined plane and pulley.

3 0

3 years ago

For a given velocity of projection in a projectile motion, the maximum horizontal distance is possible only at ө = 45°. Substant

myrzilka [38]

First let us imagine the projectile launched at initial velocity V and at angle θ relative to the horizontal. (ignore wind resistance)

Vertical component y:

The initial vertical velocity is given as Vsinθ
The moment the projectile reaches the maximum height of h, the vertical velocity will be 0, therefore the time t taken to attain this maximum height is:

h = Vsinθ - gt
0 = Vsinθ - gt
t = (Vsinθ)/g

where g is acceleration due to gravity

Horizontal component x:
The initial horizontal velocity is given as Vcosθ. However unlike the vertical component, this horizontal velocity remains constant because this is unaffected by gravity. The time to travel the horizontal distance D is twice the value of t times the horizontal velocity.
D = Vcosθ*[(2Vsinθ)/g]
D = (2V²sinθ cosθ)/g
D = (V²sin2θ)/g

In order for D (horizontal distance) to be maximum, dD/dθ = 0
That is,

2V^2 cos2θ / g = 0
And since 2V^2/g must not be equal to zero, therefore cos(2θ) = 0
This is true when 2θ = π/2 or θ = π/4

Therefore it is now<span> shown that the maximum horizontal travelled is attained when the launch angle is π/4 radians, or 45°.</span>

6 0

4 years ago

An electric field of 3x10^16 n/c is needed to create a spark in the air. If the charged particles in the field are separated by

meriva

The answer of this problem is positive 3

6 0

3 years ago

A bird flying straight upward at 5 m/s drops a berry when it is 300 m above the ground. How fast is the berry going when it hits

Nikitich [7]

Answer:

v=77.62 m/s

Explanation:

Given that

h= - 300 m

speed of the bird ,u= 5 m/s

Lets take Speed of the berry when it hit the ground = v m/s

we know that ,if object is moving upward

v² = u² - 2 g h

u=Initial speed

v=Final speed

h=Height

Now by putting the values

v² = u² - 2 g h

v² = 5² - 2 x 10 x (-300) ( take g = 10 m/s²)

v² =25 + 20 x 300

v² ==25 + 6000

v² =6025

v=77.62 m/s

Therefore the final speed of the berry will be 77.62 m/s.

5 0

3 years ago