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Aleks [24]
3 years ago
6

Lesson 7 skills practice graph on the coordinate plane

Mathematics
1 answer:
Nastasia [14]3 years ago
4 0

Answer:

Step-by-step explanation: need more info

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????????????????????
kati45 [8]

Answer:

huh I would help but what the question?

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
I don’t know how to do that
Alisiya [41]

Answer:

16

Step-by-step explanation:

Divide 64 by 8 to get 8. this is 1/8 of the books.

3/8 were non fiction, or 24

1/4 (2/8) were picture books, or 16

5/8 were non fiction or picture books, so ’the rest‘ of the chapter books is 3/8.

3/8 were chapter books, or 24.

add the amount of picture books and chapter books since they are the fictional texts.

16+24=40

subtract the amount of non fictional books from the amount of fictional books to get the sum.

40-24=16

8 0
3 years ago
Match the parabolas represented by the equations with their vertices. y = x2 + 6x + 8 y = 2x2 + 16x + 28 y = -x2 + 5x + 14 y = -
GaryK [48]

Consider all parabolas:

1.

y = x^2 + 6x + 8,\\y=x^2+6x+9-9+8,\\y=(x^2+6x+9)-1,\\y=(x+3)^2-1.

When x=-3, y=-1, then the point (-3,-1) is vertex of this first parabola.

2.

y = 2x^2 + 16x + 28=2(x^2+8x+14),\\y=2(x^2+8x+16-16+14),\\y=2((x^2+8x+16)-16+14),\\y=2((x+4)^2-2)=2(x+4)^2-4.

When x=-4, y=-4, then the point (-4,-4) is vertex of this second parabola.

3.

y =-x^2 + 5x + 14=-(x^2-5x-14),\\y=-(x^2-5x+\dfrac{25}{4}-\dfrac{25}{4}-14),\\y=-((x^2-5x+\dfrac{25}{4})-\dfrac{25}{4}-14),\\y=-((x-\dfrac{5}{2})^2-\dfrac{81}{4})=-(x-\dfrac{5}{2})^2+\dfrac{81}{4}.

When x=2.5, y=20.25, then the point (2.5,20.25) is vertex of this third parabola.

4.

y =-x^2 + 7x + 7=-(x^2-7x-7),\\y=-(x^2-7x+\dfrac{49}{4}-\dfrac{49}{4}-7),\\y=-((x^2-7x+\dfrac{49}{4})-\dfrac{49}{4}-7),\\y=-((x-\dfrac{7}{2})^2-\dfrac{77}{4})=-(x-\dfrac{7}{2})^2+\dfrac{77}{4}.

When x=3.5, y=19.25, then the point (3.5,19.25) is vertex of this fourth parabola.

5.

y =2x^2 + 7x +5=2(x^2+\dfrac{7}{2}x+\dfrac{5}{2}),\\y=2(x^2+\dfrac{7}{2}x+\dfrac{49}{16}-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x^2+\dfrac{7}{2}x+\dfrac{49}{16})-\dfrac{49}{16}+\dfrac{5}{2}),\\y=2((x+\dfrac{7}{4})^2-\dfrac{9}{16})=2(x+\dfrac{7}{4})^2-\dfrac{9}{8}.

When x=-1.75, y=-1.125, then the point (-1.75,-1.125) is vertex of this fifth parabola.

6.

y =-2x^2 + 8x +5=-2(x^2-4x-\dfrac{5}{2}),\\y=-2(x^2-4x+4-4-\dfrac{5}{2}),\\y=-2((x^2-4x+4)-4-\dfrac{5}{2}),\\y=-2((x-2)^2-\dfrac{13}{2})=-2(x-2)^2+13.

When x=2, y=13, then the point (2,13) is vertex of this sixth parabola.

3 0
3 years ago
Need help please<br>ansewer fast
Debora [2.8K]
14) 6.20

16) 9.1
 I hope that helps cuz
5 0
3 years ago
Read 2 more answers
I'd Point A is located at (9,2) on a coordinate plane and point B is located at (-9,10), what is the distance between the two po
Fiesta28 [93]
Draw the triangle and then use Pythagoras' theorem

distance = \sqrt{18 ^{2} +8 ^{2}   }
              = 19.70 (2dp) 
4 0
3 years ago
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