Start by graphing each line.
• Because the first inequality is smaller than, it will have a dotted (- - -) line.
• Because the second inequality is smaller than or equal to, it will have a solid line (---).
Then, plug in points to see where your shading will go. If the statement is true (x = x), you will shade that area along the line.
0 is less than 2.
Do the same step for the other equation. Your solution to the problem is any point that lies between the shading from both inequalities (where the blue and red meet).
The product in simplest form is (x - 4)
<em><u>Solution:</u></em>
<em><u>Given expression is:</u></em>
We have to find the product in simplest form
In the given expression,
2x + 8 = 2(x+ 4)
We know that,
Therefore,
Substitute these in given expression
Cancel the common factors,
Thus the product in simplest form is (x - 4)
Answer:
Step-by-step explanation:
The genral form of a complex number in rectangular plane is expressed as z = x+iy
In polar coordinate, z =rcos ∅+irsin∅ where;
r is the modulus = √x²+y²
∅ is teh argument = arctan y/x
Given thr complex number z = 6+6√(3)i
r = √6²+(6√3)²
r = √36+108
r = √144
r = 12
∅ = arctan 6√3/6
∅ = arctan √3
∅ = 60°
In polar form, z = 12(cos60°+isin60°)
z = 12(cosπ/3+isinπ/3)
To get the fourth root of the equation, we will use the de moivres theorem; zⁿ = rⁿ(cosn∅+isinn∅)
z^1/4 = 12^1/4(cosπ/12+isinπ/12)
When n = 1;
z1 = 12^1/4(cosπ/3+isinn/3)
z1 = 12^1/4cis(π/3)
when n = 2;
z2 = 12^1/4(cos2π/3+isin2π/3)
z2 = 12^1/4cis(2π/3)
when n = 3;
z2 = 12^1/4(cosπ+isinπ)
z2 = 12^1/4cis(π)
when n = 4;
z2 = 12^1/4(cos4π/3+isin4π/3)
z2 = 12^1/4cis(4π/3)
