recall that the average rate of change is simply the slope.
![\bf \begin{array}{|cc|ll} \cline{1-2} years&price\\ \cline{1-2} 0&0.90\\ 5&1.20\\ \cline{1-2} \end{array}~\hfill (\stackrel{x_1}{0}~,~\stackrel{y_1}{0.90})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{1.20}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1.20-0.90}{5-0}\implies \cfrac{0.30}{5}\implies \stackrel{\textit{6 cents per year}}{0.06}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7B%7Ccc%7Cll%7D%20%5Ccline%7B1-2%7D%20years%26price%5C%5C%20%5Ccline%7B1-2%7D%200%260.90%5C%5C%205%261.20%5C%5C%20%5Ccline%7B1-2%7D%20%5Cend%7Barray%7D~%5Chfill%20%28%5Cstackrel%7Bx_1%7D%7B0%7D~%2C~%5Cstackrel%7By_1%7D%7B0.90%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B5%7D~%2C~%5Cstackrel%7By_2%7D%7B1.20%7D%29%20%5C%5C%5C%5C%5C%5C%20slope%20%3D%20m%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%7B%20y_2-%20y_1%7D%7D%7B%5Cstackrel%7Brun%7D%7B%20x_2-%20x_1%7D%7D%5Cimplies%20%5Ccfrac%7B1.20-0.90%7D%7B5-0%7D%5Cimplies%20%5Ccfrac%7B0.30%7D%7B5%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7B6%20cents%20per%20year%7D%7D%7B0.06%7D)
Answer:
By year 2092
Step-by-step explanation:
In this question, we are asked to calculate the year at which the population of the city will reach 178,000
The equation that models the population of the city is given as;
A = 119e^0.027t
Here, we plug A to be 178,000
178000 = 119e^0.027t
we take the natural logarithm of both sides)
ln 178,000 = ln (119e^0.027t)
12.09 = 0.027t ln 119
12.09/ln 119 = 0.027t
2.53 = 0.027t
t = 2.53/0.027
t = 93.7 which is approximately 94 years
Since t is number of years after 1998, the exact time the population will reach 178,000 will be 1998 + 94 years = 2,092
Hayden bought 36 baseball cards because 3/4 represents three quartersof a given amount
Answer:
-4
Step-by-step explanation:
down 4, right 1
-4/1
Answer: because djsjs
Step-by-step explanation: