-2+4 is 2/2 is (1,y)
4+0 divided by 2 is 2
coordinate is (1,2)
2/5 plus 27/9 minus 0 equals 0
Answer: 
Step-by-step explanation:
The range is the set of output values for the domain (the set of inputs).
- When x=-5, y=
. - When x=0,
. - When x=2,
So, the range is 
We take the equation <span>d = -16t^2+12t</span> and subtract d from both sides to get
0<span> = -16t^2+12t - d
We apply the quadratic formula to solve for t. With a = -16, b = 12, c = -d, we have
t = [ -(12) </span><span>± √( 12^2 - 4(-16)(-d) ) ] / [2 * -16]</span>
= [- 12 ± √(144-64d) ] / (-32)
= [- 12 ± √16(9-4d)] / (-32)
= [- 12 ± 4√(9-4d)] / (-32)
= 3/8 ±√(9-4d) / 8
The answer to your question is t = 3/8 ±√(9-4d) / 8
