3 years ago

Please help if you can.

Mathematics

1 answer:

Rudiy273 years ago

4 0

Uhhhhhhhhhh.......:)

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3 years ago

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The rocket would be in the air for 8.125 seconds after launch.

Step-by-step explanation:

Given that the height of the rocket, h = 260t - 16 $t^{2}$ .

To determine how long the rocket would be in the air, differentiate h totally with respect to t.

So that, total derivative of h is given as;

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0 = 260 - 32t

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