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Readme [11.4K]
4 years ago
13

How many moles in 5 grams of gold

Chemistry
2 answers:
Ainat [17]4 years ago
8 0
There is 0.02538502095915 Moles in 5 grams of gold.
alekssr [168]4 years ago
4 0
Moles of Gold = Mass of Gold ÷ Molar Mass of Gold
          
                       =  5 g  ÷  197 g/mol
 
                       ≈  0.0253 mol

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If a steel container holds 3.50 moles of hydrogen gas and 3.50 moles of helium gas, and the total pressure is 4.00 atm., what is
Sunny_sXe [5.5K]

Answer:

1. Partial pressure of H₂ = 2 atm

2. Partial pressure of He = 2 atm

Explanation:

The following data were obtained from the question:

Mole of H₂ = 3.50 moles

Mole of He = 3.50 moles

Total pressure (Pₜ) = 4 atm

Partial pressure of H₂ =?

Partial pressure of He =?

Next, we shall determine the mole fraction of each gas this can be obtained as follow:

Mole of H₂ = 3.50 moles

Mole of He = 3.50 moles

Total mole = Mole of H₂ + Mole of He

Total mole = 3.50 + 3.50

Total mole = 7 moles

Mole fraction of H₂ = mole of H₂ / Total mole

Mole fraction of H₂ = 3.5/7

Mole fraction of H₂ = 0.5

Mole fraction of He = mole of He / Total mole

Mole fraction of He = 3.5/7

Mole fraction of He = 0.5

1. Determination of the partial pressure of H₂.

Mole fraction of H₂ = 0.5

Total pressure (Pₜ) = 4 atm

Partial pressure of H₂ =?

Partial pressure of H₂ = Mole fraction of H₂ × Pₜ

Partial pressure of H₂ = 0.5 × 4

Partial pressure of H₂ = 2 atm

2. Determination of the partial pressure of He.

Total pressure (Pₜ) = 4 atm

Partial pressure of H₂ = 2 atm

Partial pressure of He =?

Total pressure (Pₜ) = Partial pressure of H₂ + Partial pressure of He

4 = 2 + Partial pressure of He

Collect like terms

Partial pressure of He = 4 – 2

Partial pressure of He = 2 atm

6 0
3 years ago
Determine the number of atoms and the mass of zirconium, silicon and oxygen found in 0.3384 Mol of zircon ZrSiO4, a
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Explanation:

1 mol of ZrSiO₄ , have , 1 mol of Zr , 1 mol of Si and  4 mol of  Oxygen .

since ,

1 mol of a substance have 6.022 * 10 ²³ particles ,

From the question ,

0.3384 mol of zircon ZrSiO₄ ,

hence ,

from the above equation ,

1 mol of a substance have 6.022 * 10 ²³ particles ,

0.3384 mol = 0.3384 * 6.022 * 10 ²³ number of atoms

                  = 2.037 * 10 ²³ number of atoms

Hence ,

0.3384 mol of ZrSiO₄ will have , 0.3384 mol of Zr ,0.3384 mol of Si and  4*0.3384 mol of  Oxygen .

Hence ,

  • number of atoms of Zr = 0.3384 mol * 6.022 * 10 ²³ = 2.037 * 10 ²³ number of atoms
  • number of atoms of Si = 0.3384 mol * 6.022 * 10 ²³ = 2.037 * 10 ²³ number of atoms
  • number of atoms of O = 4 * 0.3384 mol * 6.022 * 10 ²³ = 8.148 * 10 ²³ number of atoms

The mass is calculated as -

since ,

Moles is denoted by given mass divided by the molecular mass ,  

Hence ,  

n = w / m

n = moles ,  

w = given mass ,  

m = molecular mass .

n = w / m

w = n * m

  • mass of Zr ,

Since we know , the molecular mass of Zr = 91 g/mol

moles of Zr = 0.3384 mol

using the above formula ,

w = n * m

w = 0.3384 mol  * 91 g/mol = 30.79 g

hence ,

The mass of Zr = 30.79 g

  • mass of Si ,

Since we know , the molecular mass of Si = 28 g/mol

moles of Si = 0.3384 mol

using the above formula ,

w = n * m

w = 0.3384 mol  * 28 g/mol = 9.475 g

hence ,

The mass of Si = 9.475 g

  • mass of O ,

Since we know , the molecular mass of O = 16 g/mol

moles of Si = 1.3536 mol

using the above formula ,

w = n * m

w = 1.3536 mol  * 16 g/mol = 21.65 g

hence ,  

The mass of O = 21.65 g

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