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777dan777 [17]
2 years ago
13

You observe heat, light, and sound released by a chemical reaction. This reaction is (2 points)

Chemistry
1 answer:
OLEGan [10]2 years ago
3 0
Exothermic reaction.
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KHP is a monoprotic acid which provides one H+ ion. How would your results be affected if a diprotic acid (such as sulfuric acid
kari74 [83]

Explanation:

A.

In a diprotic acid, 2 moles of H+ ions is released. Therefore, number of moles of H+ in a diprotic acid = 2 × number of moles of H+ of monoprotic acid.

B.

Equation of the reaction

2NaOH + H2SO4 --> Na2SO4 + 2H2O

Number of moles of H2SO4 = molar concentration × volume

= 0.75 × 0.0105

= 0.007875 moles.

By stoichiometry, since 1 mole of H2SO4 reacts with 2 moles of NaOH. Therefore, number of moles of NaOH = 2 × 0.007875

= 0.01575 moles.

Molar concentration of NaOH = number of moles ÷ volume

= 0.01575 ÷ 0.0175

= 0.9 M of NaOH.

7 0
2 years ago
Please help!
Misha Larkins [42]
Your answer is D, OH-! correct me if I’m wrong.
4 0
2 years ago
What is the difference between a heterogeneous mixture and homogeneous mixture?
Fiesta28 [93]
A homogeneous mixture has the same uniform appearance and composition throughout


A heterogeneous mixture consists of visibly different substances or phases.
7 0
3 years ago
Which relationship or statement best describes delta s for the following reaction:
zalisa [80]

Answer:

b) Delta S < 0

Explanation:

The change in the entropy (ΔS) is related to the change in the number of gaseous moles of the reaction: Δn(g) = n(g, products) - n(g, reactants).

  • If Δn(g) > 0, the entropy increases (ΔS > 0).
  • If Δn(g) < 0, the entropy decreases (ΔS < 0).
  • If Δn(g) = 0, there is little or no change in the entropy

Let's consider the following equation.

2 H₂S(g) + 3 O₂(g) → 2 H₂O(g)

Δn(g) = 2 - 5 = - 3. Since Δn(g) < 0, the entropy decreases and ΔS < 0.

4 0
2 years ago
Calculate the volume of this regular solid.
nataly862011 [7]

Answer:2,144.7

Explanation:

7 0
2 years ago
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