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3 years ago

How do you use nonmetal in a sentence?

1 answer:

7 0

Here Is A Sentence You Could Possibly Use:

"Hydrogen and Nitrogen are two examples of non-metals."

(You can replace the two given elements with whatever two non-metallic elements you like.)

Hope This Helps!

BTW, You May Want A Second Opinion Just In Case! :)

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Use Boyle's Law to explain what would happen to the volume of a helium- filled balloon if it was carried underwater by a diver t

oksano4ka [1.4K]

The deeper the diver takes the helium balloon, the more it reduces in size. This is due to the pressure of the water column above pressing on the balloon. According to Boyle’s law (P= k*1/V.), as the volume of the balloon decreases, the pressure of the helium inside increases.

4 0

3 years ago

HELPP ME PLEASE!! What would be the density of a 40 g object that displaces 10 ml of water?

Snezhnost [94]

Answer:

<h2>The answer is 4.0 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 40 g

volume = 10 mL

The density of the object is

$density = \frac{40}{10} = 4 \\$

We have the final answer as

Hope this helps you

5 0

3 years ago

When a person is scared, the brain responds to the fear by directing the hormone adrenaline to be released. This is an example o

tangare [24]

Answer:

Adrenaline

Explanation:

3 0

3 years ago

What element would a metal, like sodium, most likely combine with?

OverLord2011 [107]

The answer you are looking for is "bromine". Hope this helps!

5 0

3 years ago

Read 2 more answers

Hydrogen fluoride is used in the manufacture of Freons (which destroy ozone in the stratosphere) and in the production of alumin

Lerok [7]

<u>Answer:</u> The percentage yield of HF is 73.36 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

For calcium fluoride:

Given mass of calcium fluoride = 6.25 kg = 6250 g (Conversion factor: 1 kg = 1000 g)

Molar mass of calcium fluoride = 78.07 g/mol

Putting values in above equation, we get:

$\text{Moles of calcium fluoride}=\frac{6250g}{78.07g/mol}=80.05mol$

For the given chemical reaction:

$CaF_2+H_2SO_4\rightarrow CaSO_4+2HF$

By Stoichiometry of the reaction:

1 mole of calcium fluoride produces 2 moles of hydrofluoric acid

So, 80.05 moles of calcium fluoride will produce = $\frac{2}{1}\times 80.05=160.1mol$ of hydrofluoric acid

Now, calculating the theoretical yield of hydrofluoric acid using equation 1, we get:

Moles of of hydrofluoric acid = 160.1 moles

Molar mass of hydrofluoric acid = 20.01 g/mol

Putting values in equation 1, we get:

$160.1mol=\frac{\text{Theoretical yield of hydrofluoric acid}}{20.01g/mol}=3203.6g=3.20kg$

To calculate the percentage yield of hydrofluoric acid, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of hydrofluoric acid = 2.35 kg

Theoretical yield of hydrofluoric acid = 3.20 kg

Putting values in above equation, we get:

$\%\text{ yield of hydrofluoric acid}=\frac{2.35g}{3.20g}\times 100\\\\\% \text{yield of hydrofluoric acid}=73.36\%$

Hence, the percentage yield of HF is 73.36 %

4 0

3 years ago