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3 years ago

Why don't we estimate an additional number on an electrical balance?

Chemistry

1 answer:

Strike441 [17]3 years ago

6 0

Significant figures

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Which element consists of positive ions immersed in a "sea" of mobile electronsa) sulfur

Margarita [4]

Hello
Sulfur is the answer

5 0

3 years ago

Calcium hydroxide is a strong base but is not very soluble ( Ksp = 5.02 X 10-6 ). What is the pH of a saturated solution of Ca(O

Misha Larkins [42]

Answer : The pH of a saturated solution is, 12.33

Explanation : Given,

$K_{sp}$ = $5.02\times 10^{-6}$

First we have to calculate the solubility of $OH^-$ ion.

The balanced equilibrium reaction will be:

$Ca(OH)_2\rightleftharpoons Ca^{2+}+2OH^-$

Let the solubility will be, 's'.

The concentration of $Ca^{2+}$ ion = s

The concentration of $OH^-$ ion = 2s

The expression for solubility constant for this reaction will be,

$K_{sp}=[Ca^{2+}][OH^-]^2$

Let the solubility will be, 's'

$K_{sp}=(s)\times (2s)^2$

$K_{sp}=(4s)^3$

Now put the value of $K_[sp}$ in this expression, we get the solubility.

$5.02\times 10^{-6}=(4s)^3$

$s=1.079\times 10^{-2}M$

The concentration of $Ca^{2+}$ ion = s = $1.079\times 10^{-2}M$

The concentration of $OH^-$ ion = 2s = $2\times (1.079\times 10^{-2}M)=2.158\times 10^{-2}M$

First we have to calculate the pOH.

$pOH=-\log [OH^-]$

$pOH=-\log (2.158\times 10^{-2})$

$pOH=1.67$

Now we have to calculate the pH.

$pH+pOH=14\\\\pH=14-pOH\\\\pH=14-1.67=12.33$

Therefore, the pH of a saturated solution is, 12.33

7 0

3 years ago

Balance the following chemical equation: N2H4+O2→ NO2+H2O

Nadya [2.5K]

Answer:

N2H4 + 3O2 → 2NO2 + 2H2O

Explanation:

4 0

3 years ago

A bike tire at a pressure of 2.4 atm and a

hjlf

Answer:

5.4 atm

Explanation:

P•V/T = P'•V'/T'

2.4•2.2/290 = P'•2/296

5.28/290 = P'/296 Multiply both sides by 296

1562.88/290 = P'

I'm = 5.4 atm

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3 years ago

How many moles are in 4.99x1032 molecules of H2o

bogdanovich [222]

Answer:

n≈8,29×10⁸ moles

Explanation:

Nᴀ=6.02×10²³ (constant)

n=N/Nᴀ=

$= \frac{ {4.99 \times 10}^{32} }{6.02 \times 10 ^{23} } = 828903654$

≈8,29×10⁸ moles

5 0

4 years ago

Why don't we estimate an additional number on an electrical balance?​

Why don't we estimate an additional number on an electrical balance?