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hichkok12 [17]
3 years ago
12

Please help it’s irritating when I keep having to post this and no ones bothering to even help me. Like I need to turn this is A

SAP

Mathematics
1 answer:
sukhopar [10]3 years ago
6 0

Measure of E is congruent to K, so E is 50 degrees.

Measure of G is congruent to L, so G is 105 degrees.

Measure of F is congruent to J, J is 180 deg - 50 deg - 105 deg = 25 degrees, so F is 25 degrees.

<u><em>The proof I am using is the Corresponding Angles Postulate.</em></u>

<u><em /></u>

I NEED BRAINLIEST!

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The moon takes 28 days to orbit around the earth going at a distance of 2,413,000. How many kilometers does it take for the moon
Mazyrski [523]

Answer:

As per the statement;

The moon takes 28 days to orbit around the earth going at a distance of 2,413,000 km

From the above information,

The ratio between Distance and Days is; \frac{2413000}{28}

then,

the distance it takes for the moon to travel one day of its orbit around the earth we have;

\frac{2413000}{28} \times 1 = \frac{2413000}{28}=86178.57 km.

Therefore, the distance in kilometer does the moon cover in 1 day is 86178.57 km


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3 years ago
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the state sales tax in pennsylvania is 0.06 (or 6%). if your total bill at the music store included $3.03 in sales tax, how much
Sedbober [7]
The answer is: 50.5

Solution:

3.03 x 100 = 303
303 ÷ 6 = 50.5
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3 years ago
Solve for x: x^2+4x-5=16x
BigorU [14]
Solve for x: x^2+4x-5=16x
first take 16x from both sides of the equation
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x=-b plus or minus the square root of b²-4ac all divided by 2a
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plug these numbers into the formula
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6 0
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Please help me! This is one of the questions on my Geometry work!
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7 0
3 years ago
The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.
Mama L [17]

Answer:

a) P(Y > 76) = 0.0122

b) i) P(both of them will be more than 76 inches tall) = 0.00015

   ii) P(Y > 76) = 0.0007

Step-by-step explanation:

Given - The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.

To find - (a) If a man is chosen at random from the population, find

                    the probability that he will be more than 76 inches tall.

              (b) If two men are chosen at random from the population, find

                    the probability that

                    (i) both of them will be more than 76 inches tall;

                    (ii) their mean height will be more than 76 inches.

Proof -

a)

P(Y > 76) = P(Y - mean > 76 - mean)

                 = P( \frac{( Y- mean)}{S.D}) > \frac{( 76- mean)}{S.D})

                 = P(Z >  \frac{( 76- mean)}{S.D})

                 = P(Z > \frac{76 - 69.7}{2.8})

                 = P(Z > 2.25)

                 = 1 - P(Z  ≤ 2.25)

                 = 0.0122

⇒P(Y > 76) = 0.0122

b)

(i)

P(both of them will be more than 76 inches tall) = (0.0122)²

                                                                           = 0.00015

⇒P(both of them will be more than 76 inches tall) = 0.00015

(ii)

Given that,

Mean = 69.7,

\frac{S.D}{\sqrt{N} } = 1.979899,

Now,

P(Y > 76) = P(Y - mean > 76 - mean)

                 = P( \frac{( Y- mean)}{\frac{S.D}{\sqrt{N} } })) > \frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } })

                 = P(Z > \frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } })

                 = P(Z > \frac{( 76- 69.7)}{1.979899 }))

                 = P(Z > 3.182)

                 = 1 - P(Z ≤ 3.182)

                 = 0.0007

⇒P(Y > 76) = 0.0007

6 0
3 years ago
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