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guapka [62]
3 years ago
6

An unstable nucleus which has a tendency to spontaneously change its form with the emission of high-energy particles or photons

is said to be _____________
Physics
2 answers:
Bezzdna [24]3 years ago
8 0

Answer: Radioactive nucleus.

Explanation: First, we can define the radiation as the emanation of particles or photons, for example, a flashlight is radiating photons when it is turned on.

So a neutron that emanates particles or photons when change form, is a nucleus that radiates, and those are called "radioactive nucleus"

Where radioactive implies that there is a presence of radiation in some way. In this case, the radiation is caused because the nucleus goes from an energetic state to other with lower energy, and that energy must be dissipated in some way, in this case, in form of radiation.

Pepsi [2]3 years ago
6 0

Answer:Radioactive

Explanation:

The radioactive nucleus is the one which does not has enough binding energy to hold the nucleus in a stable state and thus radiates either electron or proton to become a stable element.

A radioactive element is formed when after billions of years such as uranium and thorium. The stability of the nucleus depends upon the opposition of attractive and repulsive force among the nucleus.

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You are riding a bicycle. If you apply a forward force of 150 N, and you and the bicycle have a combined mass of 90 kg, what wil
bekas [8.4K]
<h3>Hello There!!</h3>

<h3><u>Given</u>,</h3>

Force(F) = 150N

Mass(m) = 90kg

<h3><u>To </u><u>Find,</u></h3>

Acceleration(a) = ?

<h3><u>We know,</u></h3>

F= m×a

150 = 90 \times  \text{a} \\  \\  \text{a} =  \frac{150}{90}  \\  \fbox{cancelling by 3} \\  \\   \text{ a}  = \cancel \frac{150}{90} \\  \\ \text{ a}  =  \frac{5}{3}  = 1.67 \text{m/s} {}^{2}

\therefore  \text{Option A= 1.67 m/s² is the correct answer}

<h3>Hope this helps</h3>
6 0
2 years ago
Un avión de rescate en Alaska deja caer un paquete de provisiones a un grupo de exploradores extraviados. Si el avión viaja hori
posledela

Answer:

180.4 m

Explanation:

The package in relation to the point where it was released falls a certain distance that is calculated by applying the horizontal motion formulas , as the horizontal speed of the plane and the height above the ground are known, the time that It takes the package to reach its destination and then the horizontal distance (x) is calculated from where it was dropped, as follows:    

$V_{ox}=v_x = 40 \ m/s$

   h = 100 m  

    x =?

     Height formula h:

     $h=g \times \frac{t^2}{2}$

      Time t is cleared:

     $t = \sqrt{\frac{2h}{g}}$

      $t = \sqrt{\frac{2 \times 100}{9.8}}$

      t = 4.51 sec

 Horizontal distance formula x:

       $x=V_x \times t$

        x = 40 m / sec x 4.51 sec

        x = 180.4 m

4 0
3 years ago
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