I would say the answer to your question is A Ferris wheel turning at a constant speed. The reasoning behind this answer is the fact that traveling in a constant direction at a constant speed is not accelerating. The Ferris wheel is the only option that fits this description. The last option would be incorrect due to independent causes such as speed limit changes as well as turns and stops on the highway.
Answer:
b. jury wasn't on ayesha akter
Answer:
velocity during second d = 20.0 mi/h
Explanation:
Total distance travelled is 2d, with an average velocity of 30.0 mi/h you can express the time travelled in terms of d:
distance = velocity * time
time = distance / velocity
time = 2d/30.0
The time needed for the first d at 60.0 is:
time = d/60.0
The time in the second d you can get it by substracting both times (total time - time for the first d)
second d time = 2d/30.0 - d/60.0
= 4d/60.0 - d/60.0
= 3d/60.0
and with the time (3d/60.0) and the distance travelled (d) you can get the velocity:
velocity = distance / time
velocity = d / (3d/60.0)
= 60.0/3 = 20.0 mi/h
Answer:
![\Delta V=\Delta V_1+\Delta V_2+\Delta V_3](https://tex.z-dn.net/?f=%5CDelta%20V%3D%5CDelta%20V_1%2B%5CDelta%20V_2%2B%5CDelta%20V_3)
Explanation:
We are given that three resistors R1, R2 and R3 are connected in series.
Let
Potential difference across ![R_1=\Delta V_1](https://tex.z-dn.net/?f=R_1%3D%5CDelta%20V_1)
Potential difference across ![R_2=\Delta V_2](https://tex.z-dn.net/?f=R_2%3D%5CDelta%20V_2)
Potential difference across ![R_3=\Delta V_3](https://tex.z-dn.net/?f=R_3%3D%5CDelta%20V_3)
We know that in series combination
Potential difference ,![V=V_1+V_2+V_3](https://tex.z-dn.net/?f=V%3DV_1%2BV_2%2BV_3)
Using the formula
![\Delta V=\Delta V_1+\Delta V_2+\Delta V_3](https://tex.z-dn.net/?f=%5CDelta%20V%3D%5CDelta%20V_1%2B%5CDelta%20V_2%2B%5CDelta%20V_3)
Hence, this is required expression for potential difference.