Answer: 0.2 hours
Explanation: In order to solve this question we have to considerer that a recargeable battery can supply 1800 mA in one hour then we have to determine how long could this battery drive current through a long, thin wire of resistance 34 Ω .
Besides, this battery has a voltage of 12 V
so by using the Ohm law we also know that V=R*I,
Fron this we can obtain:
I= V/R= 12 V/ 34 Ω=0.35 A= 350 mA
then considering that this battery can supply 1800 mA in one hour we have this battery can supply 350 mA in x time in the form:
1hour------- 1800 mA
x hour--------350 mA
time= 350/1800= 0.2 hour
Answer:
A stone that is dropped down into an empty well
Answer:


-0.04194 V
Explanation:
= Number of turns in outer solenoid = 330
= Number of turns in inner solenoid = 22
= Current in inner solenoid = 0.14 A
= Rate of change of current = 1800 A/s
= Vacuum permeability = 
r = Radius = 0.0115 m
Magnetic field is given by

The average magnetic flux through each turn of the inner solenoid is 
Magnetic flux is given by

Mutual inductance is given by

The mutual inductance of the two solenoids is 
Induced emf is given by

The emf induced in the outer solenoid by the changing current inthe inner solenoid is -0.04194 V
The gravitational force I’d experience while I am floating outside the ISS will be 4.47 × 10⁻¹⁵ N.
<h3>What is gravitational force?</h3><h3 />
Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

Hence, the gravitational force I’d experience while I am floating outside the ISS will be 4.47 × 10⁻¹⁵ N.
To learn more about the gravitational force refer to the link;
brainly.com/question/24783651
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