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shusha [124]
3 years ago
9

For the reaction PCl5(g) + heat PCl3(g) + Cl2(g), what will happen when the pressure is increased? There will not be a shift in

equilibrium. There will be a shift toward the products. There will be a shift toward the reactants. Not enough information is given.
Chemistry
2 answers:
Gnesinka [82]3 years ago
8 0

Answer:

There will be a shift toward the reactants.

Explanation:

According to Le Chatelier’s Principle, when a stress is applied on a system in dynamic equilibrium, the equilibrium shifts in such a way to minimize or counteract the stress. In the given reaction:

PCl₅(g) –> PCl₃(g) + Cl₂(g)

both the reactants and products are gases. But there are higher moles of gaseous particles on the product side.  As the pressure is increased the equilibrium will shift in a direction to reduce the pressure. So the equilibrium will shift towards the reactant side as that side has less moles of gaseous substance.

Tamiku [17]3 years ago
6 0
When the pressure is increased, the equilibrium will shift to the left to offset the pressure increase. Equilibrium shifting to the left side is favored because the left side has fewer moles of gas than the number of moles of gas on the right-hand side and because it exerts less pressure. Therefore, the answer is there will be a shift toward the reactants. 
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It would take 8 antacid tablets to produce 120 mL of CO2 gas.
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If you have 1.29 moles of NaCl in 4 liters of solution, what is the molarity of the solution?
Illusion [34]

Answer:

0.32M

Explanation:

Given parameters:

Number of moles of NaCl  = 1.29moles

Volume of solution = 4liters  = 4dm³

Unknown:

Molarity of solution = ?

Solution:

Molarity is one the ways of expressing the concentration of a solute in a solution. It is given as;

         Molarity  = \frac{number of moles }{volume}

The unit is given as M which is mol/dm³

    Input the parameters and solve;

           Molarity  = \frac{1.29}{4}    = 0.32mol/dm³ or 0.32M

7 0
3 years ago
What is the mass (grams) of salt in 10.0 m' of ocean water? ball park-4x10's (1.000 molsalt -58.44 g salt, 1.0 L ocean water -0.
koban [17]

Answer:

3.5 × 10⁵ g of salt

Explanation:

<em>What is the mass (grams) of salt in 10.0 m³ of ocean water?</em>

We have this data:

  • 1.000 mol salt is equal to 58.44 g salt
  • 1.0 L of ocean water contains 0.60 mol of salt

We will need the following relations:

  • 1 L = 1dm³
  • 1 m³ = 10³ dm³

We can use proportions:

10.0m^{3} .\frac{10^{3}dm^{3}  }{1m^{3} } .\frac{1L}{1dm^{3} } .\frac{0.60molSalt}{1.0L} .\frac{58.44gSalt}{1molSalt} =3.5 \times 10^{5} gSalt

8 0
3 years ago
What molecules can produce more energy per gram than sugars and are used for storing energy in animals?
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The answer is lipids
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An IV bag is labeled as 0.800% w/w sodium chloride in water solution with a density of 1.036g/mL. What is the concentration of s
Goryan [66]

Answer:

[NaCl] = 0.14 M

[NaCl] = 0.14 m

Mole fraction of NaCl → 2.48×10⁻³

Explanation:

This is a problem of concentration.

0.8% w/w means that in 100 g of solution, we have 0.8 g of solute, in this case NaCl.

Let's determine the volume with the density.

Solution density = Solution mass / Solution volume

1.036 g/mL = 100 g / Solution volume

Solution volume = 100 g / 1.036 g/mL → 96.5 mL

Let's calculate molarity (mol/L)

We convert the mass to moles (mass / molar mass)

0.8 g / 58.45 g/mol = 0.0137 moles

We must convert the volume of solution to L.

Molarity is mol/L, moles of solute in L of solution.

96.5 mL . 1L/1000 mL = 0.0965 L

0.0137 mol / 0.0965 L = 0.14 M

Let's determine molality and mole fraction.

Molality are moles of solute in 1 kg of solvent (mol/kg)

Mass of solution = Mass of solute + Mass of solvent

100 g = 0.8 g + Mass of solvent

100 g - 0.8 g = Mass of solvent → 99.2 g

Then, we must convert the mass of solvent to kg

99.2 g . 1kg / 1000 g = 0.0992 kg

Molality: 0.0137 mol / 0.0992 kg  → 0.14 m

Mole fraction → moles of solute / moles of solute + moles of solvent

Let's find out the moles of solvent ( mass / molar mass)

99.2g / 18 g/mol = 5.511 mol

Total moles = 5.511 + 0.0137 → 5.5247 moles

Mole fraction = 0.0137 / 5.5247 → 2.48×10⁻³

8 0
3 years ago
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