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love history [14]
1 year ago
14

What is the ph of a solution of h2so4 that has [h3o ] = 5.45 × 10–5 m?

Chemistry
1 answer:
zmey [24]1 year ago
8 0

The pH of a solution of sulphuric acid that has hydronium ion concentration is 4.26.

<h3>How do we calculate pH?</h3>

pH of any solution is define as the negative logarithm of the concentration of H⁺ ion present in any solution, i.e.

pH = -log[H⁺]

In the question, it is given that:

Concentration of hydronium ion or H⁺ ion = 5.45×10⁻⁵ M

So, pH will be:
pH = -log(5.45×10⁻⁵)

pH = -(-4.26)

pH = 4.26

Hence required pH is 4.26.

To know more about pH, visit the below link:

brainly.com/question/172153

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A flashbulb of volume 2.70 mL contains O2(g) at a pressure of 2.30 atm and a temperature of 30.0 °C. How many grams of O2(g) doe
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P = 2.30 atm

Volume in liter = 2.70 mL / 1000 => 0.0027 L

Temperature in K = 30.0 + 273 => 303 K

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number of moles O2 :

P * V = n * R* T

2.30 * 0.0027 = n * 0.082 * 303

0.00621 = n * 24.846

n = 0.00621 / 24.846

n = 0.0002499 moles of O2

Mass of O2:

n = m / mm

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m = 0.0002499 * 31.9988

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3 0
3 years ago
Does anyone know how to find mass of NaN3?
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Calculate the ph of the solution resulting by mixing 20.0 ml of 0.15 m hcl with 20.0 ml of 0.10 m koh
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Answer:

1.60.

Explanation:

  • The no. of millimoles of HCl = MV = (0.15 M)(20.0 mL) = 3.0 mmol.
  • The no. of millimoles of KOH = MV = (0.10 M)(20.0 mL) = 2.0 mmol.

<em>Since the no. of millimoles of HCl is larger than that of KOH. The solution is acidic.</em>

<em></em>

∴ M of remaining HCl [H⁺] remaining = (NV)HCl - (NV)KOH/V total = (3.0 mmol) - (2.0 mmol) / (40.0 mL) = 0.025 M.

∵ pH = - log[H⁺]

<em>∴ pH = - log[H⁺] </em>= - log(0.025) = <em>1.602 ≅ 1.60.</em>

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