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Karo-lina-s [1.5K]
2 years ago
14

If 82.5 mol of an ideal gas occupies 10.5 l at 317 k, what is the pressure of the gas?

Chemistry
1 answer:
Natali5045456 [20]2 years ago
8 0

P=20707.7 atm

<h3>What is the molar form of the ideal gas law?</h3>

The ideal gas law is a straightforward formula that describes the relationship between an ideal gas's pressure P, volume V, and temperature T. Unless there is a strong reason to treat gases differently, we normally treat gases as ideal because of how straightforward this relationship is:-

PV=nRT

where ;

P= Pressure=?

V= Volume= 10.5 L

n= no.of mol.= 82.5 mol

R=Ideal gas constant= 8.314 joule / mol kelvin

T=Temperature= 317 K

using Given value:-

P= nRT/ V

P=(82.5 x 8.314 x 317) / 10.5

P=20707.7 atm

Learn more about Ideal gas law here:-

brainly.com/question/15132707

#SPJ4

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PLEASE HELP!!!!!!!
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Answer: 1. 2Al+3CuCl_2\rightarrow 2AlCl_3+3Cu

2. 3 moles of CuCl_2 : 2 moles of Al

3. 0.33 moles of CuCl_2 : 0.92 moles of Al

4. CuCl_2 is the limiting reagent and Al is the excess reagent.

5. Theoretical yield of AlCl_3 is 29.3 g

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

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The balanced chemical equation is:

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Thus 0.33 moles of CuCl_2 will require=\frac{2}{3}\times 0.33=0.22moles  of Al

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As 3 moles of CuCl_2 give = 2 moles of AlCl_3

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Theoretical yield of AlCl_3=moles\times {\text {Molar mass}}=0.22moles\times 133.34g/mol=29.3

Thus 29.3 g of aluminium chloride is formed.

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