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t=(0-(250sin75)^2)/-9.8
<span>the distance one is (2500+610)- (250m/s*cos75)*t=Dh Dh=horizontal distance </span>
<span>the max height one is d=0.5*9.8*t^2 </span>
<span>d= max height subtract 1800-d</span>
Answer: If both gases undergo the same entropy then more heat is added to gas a because the entropy of the gas a is less than the entropy of the gas b.
Explanation:
Entropy is defined as the degree of randomness. When the temperature of the gas increases then the entropy of gas also increases.
In the given problem, Quantity a of an ideal gas is at absolute temperature t, and a second quantity b of the same gas is at absolute temperature 2t.
Heat is added to each gas, and both gases are allowed to expand isothermally. It means that the volume is constant during this process.
If both gases undergo the same entropy then more heat is added to gas a because the entropy of the gas a is less than the entropy of the gas b. If the heat is added then there will be more entropy.
Answer:
<h2>e. 7.1 MN approx.</h2>
Explanation:
Step one:
given data
density of water= 1000kg/m^3
the dimension of the barge
width= 10m
length= 60m
depth of the boat in the water= 1.2m
Hence the volume occupied by the boat is
volume=10*60*1.2
volume= 720m^2
Step two:
Required is the weight of the barge
we can first find the mass using the relation
density = mass/volume
mass= density*volume
mass= 1000*720
mass= 720000kg
Step three:
Weight =mg
g=9.81m/s^2
W=720000*9.81
W=7063200N
divided by 10^6
W=7.06MN
W=7.1MN approx.
Answer:
two ampheres
Explanation:
the formula for calculating voltage is V=IR so if the current which is I is 2 and the resistance which is R is decreased to one forth then we will say
R=x multiplied by 1/4=x/4
V=2x/4 cross multiply then we have
since the voltage is constant then it is=1
so 4=2x divide both sides by 2 we then get 2 as our answer
Answer:
solid
Explanation:
they molecules are closely together
