Mechanical advantage is a measure of how much a machine multiplies the input

A) Find the gravitational field strength of an asteroid with the mass of 3.2 * 10^3 kg and an average radius of 30 km when at a

MrMuchimi

a) $1.96\cdot 10^{-16} m/s^2$

The gravitational field strength near the surface of the asteroid is given by:

$g=\frac{GM}{(R+h)^2}$

where

G is the gravitational constant

M is the mass of the asteroid

R the radius of the asteroid

h is the distance from the surface

Substituting the data of the asteroid:

$M=3.2\cdot 10^3 kg$ is the mass

$R=30 km = 30000 m$ is the radius of the asteroid

$h=3 km = 3000 m$ is the distance from the surface

We find

$g=\frac{(6.67\cdot 10^{-11})(3.2\cdot 10^3)}{(30000+3000)^2}=1.96\cdot 10^{-16} m/s^2$

b) i) $5.53\cdot 10^9 s$

The acceleration of the astronaut popped out at 3 km from the surface is exactly that calculated at part a):

$g=1.96\cdot 10^{-16} m/s^2$

So, since its motion is at constant acceleration, we can find the time he takes to reach the surface using suvat equations:

$s=ut+\frac{1}{2}gt^2$

where

s = 3 km = 3000 m is his displacement to reach the surface

u = 0 is his initial velocity

t is the time

Solving for t,

$t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(3000)}{1.96\cdot 10^{-16} m/s^2}}=5.53\cdot 10^9 s$

b) ii) $1.08\cdot 10^{-6} m/s$

Again, we can use another suvat equation:

$v=u+gt$

where

v is the final velocity

u is the initial velocity

g is the acceleration of gravity

t is the time

Since we have

u = 0

$t=5.53\cdot 10^9 s$

$g=1.96\cdot 10^{-16} m/s^2$

The velocity of the astronaut at the surface will be

$v=0+(1.96\cdot 10^{-16} m/s^2)(5.53\cdot 10^9)=1.08\cdot 10^{-6} m/s$

b) iii) 175 years

The duration of one year here is

$T=3.16\cdot 10^7 s$

And the time it takes for the astronaut to reach the surface of the asteroid is

$t=5.53\cdot 10^9 s$

Therefore, to find the number of years, we just need to divide the total time by the duration of one year:

$n=\frac{t}{T}=\frac{5.53\cdot 10^9 s}{3.16\cdot 10^7}=175$

So, the astronaut will take 175 years to reach the surface.

8 0

4 years ago

How does the mass of an astronaut change when she travels from earth to the moon? how does her weight change?

Elza [17]

Her weight doesn't change but thats only simply because there is no gravity in space.

6 0

3 years ago

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Which statement is a scientific theory?

Dmitry [639]

Answer:

I think it is D

Explanation:

7 0

3 years ago

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Bob is pulling a 30kg filing cabinet with a force of 200N , but the filing cabinet refuses to move. The coefficient of static fr

vredina [299]

Answer:

$2.0\cdot 10^2 N$

Explanation:

The cabinet does not move: this means that the net force acting on it is zero.

Along the horizontal direction, we have two forces:

- The push exerted by Bob, F = 200 N, forward

- The frictional force, $F_f$ , which acts in the opposite direction (backward)

Since the net force must be zero, we have:

$F-F_f = 0$

So solving the equation we can find the magnitude of the friction force:

$F_f = F = 200 N=2.0 \cdot 10^2 N$

7 0

4 years ago

What is wind or wind currents? I'm on that subject and don't get what it is. for the subject, I chose "Physics" because I don't

Licemer1 [7]

Explanation:

Wind Currents. currents of the surface waters of oceans and seas resulting from the action of wind on the surface of the water: Wind currents arise owing to the combined influence of the forces of friction, turbulent viscosity, pressure gradient, deflecting force of the earth's rotation, and so on.

6 0

4 years ago

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