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3 years ago

7

Logan works at a florist. He earns $900 per week plus $8 for each floral arrangement he delivers. The expression 900 + 8f gives

the amount in dollars that Logan earns for delivering f floral arrangements. How much will Logan earn if he delivers 50 floral arrangements in one week?

1 answer:

Svetllana [295]3 years ago

7 0

Answer:

900+ 8f

900+ 8(50)

= 1300

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maxonik [38]

${\qquad\qquad\huge\underline{{\sf Answer}}}$

let's solve ~

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$\qquad \sf \dashrightarrow \: 9y - 18 = 7y - 4$

[ denominator is same, so numerator must have same value to be equal ]

$\qquad \sf \dashrightarrow \: 9y - 7y = - 4 + 18$

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$\qquad \sf \dashrightarrow \: y = 7$

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2 years ago

Determine which ordered pair is NOT a solution of y=3x-8

PtichkaEL [24]

For (8, 16): 3(8) - 8 = 24 - 8 = 16 [solution]
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For (-6, -26): 3(-6) - 8 = -18 - 8 = -26 [solution]
For (-10, -38): 3(-10) - 8 = -30 - 8 = -38 [solution]

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3 years ago

Marla bought one necklace and two bracelets for $67.50. Use the following information to determine the amount she paid for each

wlad13 [49]

So if the necklace was $27 then we need to do 67.50-27=40.50, so that mans each of the bracelets cost $20.25.

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3 years ago

Jayden and Sheridan both tried to find the missing side of the right triangle. A right triangle is shown. One leg is labeled as

stellarik [79]

Answer:

Sheridan's Work is correct

Step-by-step explanation:

we know that

The lengths side of a right triangle must satisfy the Pythagoras Theorem

$c^{2}=a^{2}+b^{2}$

where

a and b are the legs

c is the hypotenuse (the greater side)

In this problem

Let

$a=7\ cm\\c=13\ cm$

substitute

$13^{2}=7^{2}+b^{2}$

Solve for b

$169=49+b^{2}$

$b^{2}=169-49$

$b^{2}=120$

$b=\sqrt{120}\ cm$

$b=10.95\ cm$

we have that

<em>Jayden's Work</em>

$a^{2}+b^{2}=c^{2}$

$a=7\ cm\\b=13\ cm$

substitute and solve for c

$7^{2}+13^{2}=c^{2}$

$49+169=c^{2}$

$218=c^{2}$

$c=\sqrt{218}\ cm$

$c=14.76\ cm$

Jayden's Work is incorrect, because the missing side is not the hypotenuse of the right triangle

<em>Sheridan's Work</em>

$a^{2}+b^{2}=c^{2}$

$a=7\ cm\\c=13\ cm$

substitute

$7^{2}+b^{2}=13^{2}$

Solve for b

$49+b^{2}=169$

$b^{2}=169-49$

$b^{2}=120$

$b=\sqrt{120}\ cm$

$b=10.95\ cm$

therefore

Sheridan's Work is correct

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Read 2 more answers

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Nastasia [14]

Answer:

30 is the wrong one because it is not a factor of 100

30 60 90 120

20 40 60 80 100

Step-by-step explanation:

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