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elena55 [62]
3 years ago
13

Latesha buys some tennis balls at $1 each and rackets at $12 each for her PE class. She buys twice as many balls as rackets. She

spends $92 in total, which includes $8 tax Which equation would you use to find the number of rackets she buys? Let x represent the number of rackets she buys. O A. 12 (x) + 1 (2x) + 8 - 92 O B. 12 (2x) +1(x) + 8 - 92 O c. x + 2x + 8 - 92 OD. 12 (x) + 1 (2.x) = 92​

Mathematics
1 answer:
marysya [2.9K]3 years ago
3 0
I would go with A it makes most sense to me .
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Fiano borrowed $550. Four months later, he sent a cheque for $562.83 to repay the loan and interest. What was the interest rate
Digiron [165]

Answer:

Rate = 0.7%

Step-by-step explanation:

Rate = Interest / (principal x time)

rate = 12.83 / ((550) x 12/4)

rate = 12.83 / (550 x 3)

rate = 12.83 / 1650

rate = 0.007

rate = 0.7%

4 0
3 years ago
What is five and one sixth plus negative three and one sixth
trasher [3.6K]
Answer: 2
5 1/6 + -3 1/6=
2
Say that 5+-3 is 2, which it is, and then just take away both of those 1/6 . Which leaves you with 2 because both of the 1/6’s cancel out.
8 0
3 years ago
On Wednesday, mr. miles walked and ran 9/10 of the trail. Then he walked 1\8 of the trail back and stopped to rest. What fractio
valentinak56 [21]

Answer:

31/40 of the trail

Step-by-step explanation:

he completed 9/10 of the trail (or 72/80 because 9*8 is 72)

He went back 1/8 of the trail (or 10/80 because 1*10 is 10)

72-10 is 62


he went 62/80, simplified is 31/40 of the trail

7 0
3 years ago
Read 2 more answers
The recursive rule for a geometric sequence is given.
barxatty [35]
Answer: The explicit rule for the geometric sequence is:
an=(2/5) (5)^(n-1), for n=1, 2, 3, 4, ...

Solution:

a1=2/5
an=5 (an-1)

n=2→a2=5 (a2-1)= 5 (a1)= 5 (2/5)→a2= (2/5) (5)
n=3→a3= 5 (a3-1)= 5 (a2)= 5 [(2/5) (5)]=(2/5) (5)^(1+1)→ a3=(2/5) (5)^2
n=4→a4= 5 (a4-1)= 5 (a3)= 5 [(2/5) (5)^2]= (2/5) (5)^(2+1)→ a4=(2/5) (5)^3

a1=2/5=(2/5) (1)=(2/5) (5)^0→a1=(2/5) (5)^(1-1)
a2=(2/5) (5)=(2/5) (5)^1→a2=(2/5) (5)^(2-1)
a3=(2/5) (5)^2→a3=(2/5) (5)^(3-1)
a4=(2/5) (5)^3→a4=(2/5) (5)^(4-1)

Then:
an=(2/5) (5)^(n-1), for n=1, 2, 3, 4, ...
5 0
3 years ago
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Which is an equation for line { in the
Mekhanik [1.2K]

Answer:

b

Step-by-step explanation:

7 0
3 years ago
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