The Cena can take 7 courses
We have given that the karate charges $35 for the first course and $22.50 for each course after that. Our total is $170.
<h3>What is the condition we can write here?</h3>

for solving this linear equation
First, subtract 35 from both sides.

isolate x so divide both sides by 22.50.

Therefore we get x = 6
Remember to add the additional class, so x is actually 7.
So,the Cena can take 7 courses.
To learn more about the linear equation visit:
brainly.com/question/1549055
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Answer:
(2x^2+1)(4x+3)
Step-by-step explanation:
8x^3 + 6x^2 + 4x+3
Split into two groups
8x^3 + 6x^2 + 4x+3
Factor out 2x^2 from the first group and 1 from the second group
2x^2( 4x+3) +1( 4x+3)
Factor out (4x+3) from each group
(4x+3) (2x^2+1)
Rearranging the order
(2x^2+1)(4x+3)
Answer:
105, D, 13,9899/138530? not sure on that one
Maybe A
I don’t really know