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siniylev [52]
3 years ago
14

Choose the answer. 3. (1 pt) Which is an example of the distributive property? A. 9 • (t + 5) = 9t + 45 B. 9 • (t + 5) = (t + 5)

• 9 C. 9 • (t + 5) = (9 • t) + 5 D. 9 • (t + 5) = 9t + 5
Mathematics
2 answers:
saw5 [17]3 years ago
5 0
The answer is A. this is because your are multiplying by 9 throughout
Ronch [10]3 years ago
5 0

For this case, we have:

The generic definition of the distributive property is:

a (b + c) = ab + ac\\

Therefore, the option that fits the definition is given by:

9 (t + 5) = 9t + 45

where the property is verified.

Thus, the correct option is A.

Answer:

Option A

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Answer:

y=3

Step-by-step explanation:

y + 3 = -y + 9

y + y = 9 - 3

2*y = 6

y = 6/2

y = 3

6 0
2 years ago
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6 1/2 + 3.5 x 2 - 7 divided by 3<br><br> Which operation should be performed first?
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I think PEMDAS would be helpful for this.

Step-by-step explanation:

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3 years ago
There are 8 brooms in a janitors closet . What is the ratio of the number of mops to the number of brooms
wariber [46]

Answer:

the actual answer is 3/7

Step-by-step explanation:

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3 years ago
The expected number of typographical errors on a page of a certain magazine is .2. What is the probability that an article of 10
Pavel [41]

Answer:

a) The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

Step-by-step explanation:

Given : The expected number of typographical errors on a page of a certain magazine is 0.2.

To find : What is the probability that an article of 10 pages contains

(a) 0 and (b) 2 or more typographical errors?

Solution :

Applying Poisson distribution,

N\sim Pois(0.2)

P(N=r)=\frac{e^{-np}(np)^r}{r!}

where, n is the number of words in a page

and p is the probability of every word with typographical errors.

Here, n=10 and E(N)=np=0.2

a) The probability that an article of 10 pages contains 0 typographical errors.

Substitute r=0 in formula,

P(N=0)=\frac{e^{-0.2}(0.2)^0}{0!}

P(N=0)=\frac{e^{-0.2}}{1}

P(N=0)=e^{-0.2}

P(N=0)=0.8187

The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors.

Substitute r\geq 2 in formula,

P(N\geq 2)=1-P(N

P(N\geq 2)=1-[P(N=0)+P(N=1)]

P(N\geq 2)=1-[\frac{e^{-0.2}(0.2)^0}{0!}+\frac{e^{-0.2}(0.2)^1}{1!}]

P(N\geq 2)=1-[e^{-0.2}+e^{-0.2}(0.2)]

P(N\geq 2)=1-[0.8187+0.1637]

P(N\geq 2)=1-0.9825

P(N\geq 2)=0.0175

The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

6 0
3 years ago
Job A pays $13.00 per hour but has health benefits. Job B pays $11.00 per hour. Health insurance costs $3,400 per year. You expe
Nezavi [6.7K]

Answer:

a) Job A.

Step-by-step explanation:

Time, t = 2000 hours per year

Job A:

Salary = $13 per hour

Job B:

Salary = $11 per hour

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= $3400/2000

= $ 1.7 per hour

B:. Mb = $11 × 2000 = $22000

Health insurance costs 3400$ per year so while we are working our job A we have: so $11.3 × 2000 = $22600. So on job A we earn $600 per year more than on job B.

5 0
3 years ago
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