Answer:
Circumference of the can is 21.98 cm.
Step-by-step explanation:
Since, top of the cylinder can shown in the figure is in the shape of a circle
Circumference of a circle is given by the formula,
Circumference 'C' = π × Diameter
Where r = radius of the circle
Therefore, circumference of a circle with diameter 7 centimeters will be,
C = 7π
= 7 × 3.14
= 21.98 cm
Therefore, circumference of the can is 21.98 cm.
False ....a parameter is something YOU can change, like asking magazines if they are interested in sports, or interested in photography, or something else. So the 12% is a statistic.
Answer:
(This is for the pizza question)The area of the box is 900 cm, so subtract 900 cm from the area of the circle which is (3.14)[times radius which is 12(half of 24) squared] [144*3.14] So the area of the circle is 452.16 which you get from the area formula of pi times radius squared.
Step-by-step explanation:
Find the area of the box first, then subtract it by the area of the circle. (please thank me for it)
Answer:
The first statement is true.
Step-by-step explanation:
The function is f(x) = - (x + 6)(x + 2)
⇒ f(x) = - x² - 8x - 12
Now, condition for a function f(x) to be increasing at x = a is f'(a) > 0.
Now, f(x) = - x² - 8x - 12
⇒ f'(x) = -2x - 8 {Differentiating with respect to x}
Now, f'(a) = -2a - 8 {Here a can be any real value}
And, the condition for increasing function at x = a is
- 2a - 8 > 0
⇒ - 2a > 8
⇒ a < - 4
Therefore, the first statement is true i.e. the function is increasing for all real values of x where x < – 4. (Answer)
Answer: 
Step-by-step explanation:
In order to solve this exercise it is important to remember the multiplication of signs. Notice that:

In this case you have the following expression given in the exercise:

Where the variable is "j".
When you multiply signs, you get:

Now you need to identify that like terms and then you need to add them (or combine them). So, applying this procedure you get that the simplified form of the expression is the shown below:

As you can observe, you get a 2nd degree binomial.