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SVETLANKA909090 [29]
3 years ago
14

Find the slope of the line that passes through the points (10, 9) and (2, 4).

Mathematics
1 answer:
solniwko [45]3 years ago
6 0

Answer:

slope = 5/8

Step-by-step explanation:

use the slope formula to find the slope: \frac{y_2 - y_1}{x_2-x_1}

\frac{9-4}{10-2} = \frac{5}{8}

You might be interested in
In parallelogram DEFG, DH = x + 5, HF = 2y, GH = 4x-3 and HE = 4y + 1. Find the values of x and y. The diagram is not drawn to s
GalinKa [24]
Rule: The diagonals of any parallelogram bisect each other. In other words, they cut each other in half.

This means DF is cut into two equal pieces: DH and HF.
Similarly, GE is cut into two equal pieces: GH and HE.

DH = HF
x+5 = 2y
x = 2y-5

GH = HE
4x-3 = 4y+1
4(x)-3 = 4y+1
4(2y-5)-3 = 4y+1 ... x has been replaced with 2y-5
8y-20-3 = 4y+1
8y-23 = 4y+1
8y-4y = 1+23
4y = 24
y = 6

If y = 6, then x is
x = 2y-5
x = 2(6)-5
x = 12-5
x = 7

--------------------------------------------

Answers: 
x = 7 and y = 6

5 0
3 years ago
Evaluate the expression for x = -2, y = 3, z = -4. -4x + 5y + 6z *
babunello [35]

Answer:

-1

Step-by-step explanation:

Plug in given values

-4x + 5y + 6z

-4(-2) + 5(3) + 6(-4)

8 + 15 -24

23-24

-1

6 0
3 years ago
Read 2 more answers
Simplify 10 + 4(x + 1) + 5
Levart [38]
Distribute
10+4x+4+5

Combine like terms
19+4x

Final answer: 4x+19
4 0
3 years ago
A train leaves Philadelphia at 2:00 PM. A second train leaves the same city in the same direction at 4:00 PM. The second train t
polet [3.4K]

Answer: First train speed shall be 42 mi/hr

Second train speed shall be 84 mi/hr

Yes it is the valid answer, it gets annoying when almost everyone enters the wrong answer for a good laugh. Either way, hope this helps! Have a spectacular day.

Step-by-step explanation:

What is the 1st train's head start in miles?

Let +s+ = the speed of the 1st train in mi/hr

From 2PM to 4PM is 2 hrs

+d%5B1%5D+=+s%2A2+

---------------------

Let +d+ = distance the 2nd train travels until

it overtakes the 1st train

From 4PM to 6PM is 2 hrs

Start time when the 2nd train leaves

---------------------

Equation for 1st train:

(1) +d+-+2s+=+s%2A2+

Equation for 2nd train:

(2) +d+=+%28+s%2B42+%29%2A2+

--------------------

Substitute (2) into (1)

(1) +%28+s%2B42+%29%2A2+-+2s+=+s%2A2+

(1) +2s+%2B+84+-+2s+=+2s+

(1) +2s+=+84+

(1) +s+=+42+

and

+s%2B+42+=+42+%2B+42+

+s+%2B+42+=+84+

------------------

The 1st train's speed is 42 mi/hr

The 2nd train's speed is 84 mi/hr

---------------------------

check:

(2) +d+=+%28+s%2B42+%29%2A2+

(2) +d+=84%2A2+

(2) +d+=+168+

and

(1) +d+-+2s+=+s%2A2+

(1) +d+-+2%2A42+=+42%2A2+

(1) +d+=+84+%2B+84+

(1) +d+=+168+

8 0
3 years ago
Sonia uses $12.50 to buy a new journal. She has $34.25 left in her savings account. How much money did Sonia have before she bou
GalinKa [24]
So all you have to do to find out how much she had before is add up both value 12.50+34.25=   46.75$ (answer)

because y-12.50=34.25 so you would have to had the 12.5 to the other side to find the value of Y
3 0
3 years ago
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